问题
Users will be filling a field in with numbers relating to their account. Unfortunately, some users will have zeroes prefixed to the beginning of the number to make up a six digit number (e.g. 000123, 001234) and others won't (e.g. 123, 1234). I want to 'trim' the numbers from users that have been prefixed with zeros in front so if a user enters 000123, it will remove the zeroes to become 123.
I've had a look at trim and substr but I don't believe these will do the job?
回答1:
You can use ltrim() and pass the characters that should be removed as second parameter:
$input = ltrim($input, '0');
// 000123 -> 123
ltrim only removes the specified characters (default white space) from the beginning (left side) of the string.
回答2:
ltrim($usernumber, "0");
should do the job, according to the PHP Manual
回答3:
$number = "004561";
$number = intval($number, 10);
$number = (string)$number; // if you want it to again be a string
回答4:
You can always force PHP to parse this as an int. If you need to, you can convert it back to a string later
(int) "000123"
回答5:
You can drop the leading zeros by converting from a string to a number and back again. For example:
$str = '000006767';
echo ''.+$str; // echo "6767"
回答6:
Just multiply your number by zero.
$input=$input*1;
//000000123*1 = 123
来源：https://stackoverflow.com/questions/3782414/trim-any-zeros-at-the-beginning-of-a-string-using-php