问题
To read an int using scanf we use:
scanf("%d", &i);
What if i is a long not int??
Note: when using %d with long it gives me an irritating warning..
回答1:
Just use
long l;
scanf("%ld", &l);
it gives me an irritating warning..
That warning is quite right. This is begging for stack corruption.
回答2:
For gods sake:
long n;
scanf( "%ld", & n );
回答3:
scanf("%ld", &i);
You can also use "%Ld" for a long long (and depending on your compiler, sometimes also "%lld").
Take a look at the Conversions section of the scanf man page for more. (Just Google it if your system doesn't have manpages).
回答4:
Each conversion specifier expects its corresponding argument to be of a specific type; if the argument's type does not match the expected type, then the behavior is undefined. If you want to read into a long with scanf(), you need to use the %ld conversion specifier:
long i;
scanf("%ld", &i);
Check the online draft C standard (.pdf file), section 7.19.6.2, paragraph 11 for a complete listing of size modifiers and expected types.
回答5:
Check this, here is the answer: "%I64d"
来源：https://stackoverflow.com/questions/2852390/reading-long-int-using-scanf