Referencing non-final variable: why does this code compile?

问题

First off, I apologise if this is a duplicate question. I found many similar ones, but none that directly address my question.

In preparation for an upcoming exam, I am doing a past paper. It has a question that gives a code snippet. We have to state if it compiles, and if not, write the line at which the first compiler error occurs and explain it. This is the snippet:

public static void main(String[] args) {
    JFrame f = new JFrame("hi");
    JTextField jtf = new JTextField(50);

    jtf.addMouseMotionListener(new MouseMotionAdapter() {
        public void mouseMoved(MouseEvent evt) {
            jtf.setText(evt.getLocationOnScreen().toString());
        }
    });

    f.add(jtf);
    f.setVisible(true);
}

I was expecting it not to compile as jtf is not final. I tested my theory by entering the code above in Eclipse, which flagged the expected error, but compiled and ran just fine. It was only after mousing over the JTextField that I got the expected error:

java.lang.Error: Unresolved compilation problem: Cannot refer to the non-final local variable jtf defined in an enclosing scope

I did a bit of searching, and discovered that Eclipse uses its own version of the Java compiler. So I remade the file outside of Eclipse and compiled/ran it via the command line. It compiled with no errors or warnings, and when mousing over the text field, displayed the desired java.awt.Point[x=...,y=...].

My understanding of anonymous inner classes is that they can access:

Fields of the enclosing class
Methods of the enclosing class
Local variables of the enclosing scope, provided they are final

So what am I missing? According to what I know, this code should not work.

回答1:

I guess you are compiling with Java 8. Here your jtf variable is effectively final, so it compiles fine. A variable is effectively final if its value is never changed after you initialized it.

See also Local Classes:

However, starting in Java SE 8, a local class can access local variables and parameters of the enclosing block that are final or effectively final. A variable or parameter whose value is never changed after it is initialized is effectively final.

and

Accessing Local Variables of the Enclosing Scope, and Declaring and Accessing Members of the Anonymous Class

Like local classes, anonymous classes can capture variables; they have the same access to local variables of the enclosing scope:

An anonymous class has access to the members of its enclosing class.

An anonymous class cannot access local variables in its enclosing scope that are not declared as final or effectively final.

[...]

If you tried with:

javac -source 1.7 MyFile.java

you'll have your expected error.

.java:13: error: local variable jtf is accessed from within inner class; needs to be declared final
                jtf.setText(evt.getLocationOnScreen().toString());
                ^
1 error

So the answer of the exam question is: it compiles only if you're using Java 8+.

回答2:

Java 8 added the ability to access "effectively final" variables. The final keyword is no longer required as long as a variable is never changed after it is initialized.

回答3:

It may work in Java8 as the stress is on Effectively Final which means once the value is assigned to jtf it should not be changed after wards. As per Java doc:

A variable or parameter whose value is never changed after it is initialized is effectively final.

回答4:

Seems that your Eclipse IDE uses Java 7 compiler. To change this to Java 8 use Project->Properties->Java Compiler->Compiler compliance level.

来源：https://stackoverflow.com/questions/30141767/referencing-non-final-variable-why-does-this-code-compile

标签

java

java-8

inner-classes