Pass a variable number of bash command line arguments to a MATLAB function

Question

Arguments that are passed to a bash script can be passed on to a MATLAB function in the following way:

#!/bin/bash

matlab -nodesktop -nosplash -nodisplay -r "my_function('$1','$2')"

But how to do this if I do not know the number of arguments to pass a priori? So I want to do something like this:

#!/bin/bash

matlab -nodesktop -nosplash -nodisplay -r "my_function('$1',...,'$N')"

where I do not know what number N equals to a priori.

I figure that you could create a string with a for loop containing '$1',...,'$N' and pass the entire string to the above command. But isn't there a more succinct approach?

FIW, I am not fluent in bash. So if the loop is the only way to go, could you please inform me how to do this?

EDIT

I managed to devise a solution to my problem:

#!/bin/bash

INPUT=""
for var in "$@"
do
    INPUT=$INPUT"'"$var"',"
done
INPUT=${INPUT%?}

matlab -nodesktop -nosplash -nodisplay -r "my_function($INPUT)"

Isn't there a easier/shorter way to do this?

Answer 1

Taking inspiration from here:

#!/bin/bash

INPUT=$(printf "'%s'," "$@") && INPUT=${INPUT%,}

echo matlab -nodesktop -nosplash -nodisplay -r "my_function($INPUT)"

Output:

$ ./test.sh one two three
matlab -nodesktop -nosplash -nodisplay -r my_function('one','two','three')

It's a little shorter, at least.