How to ignore hidden files using os.listdir()?

My python script executes an os.listdir(path) where the path is a queue containing archives that I need to treat one by one.

The problem is that I'm getting the list in an array and then I just do a simple array.pop(0). It was working fine until I put the project in subversion. Now I get the .svn folder in my array and of course it makes my application crash.

So here is my question: is there an existing function that ignore hidden files when executing an os.listdir() and if not what would be the best way?

Thank you.

Adam Rosenfield

You can write one yourself:

def listdir_nohidden(path):
    for f in os.listdir(path):
        if not f.startswith('.'):
            yield f

Or you can use a glob:

def listdir_nohidden(path):
    return glob.glob(os.path.join(path, '*'))

Either of these will ignore all filenames beginning with '.'.

This is an old question, but seems like it is missing the obvious answer of using list comprehension, so I'm adding it here for completeness:

[f for f in os.listdir(path) if not f.startswith('.')]

As a side note, the docs state listdir will return results in 'arbitrary order' but a common use case is to have them sorted alphabetically. If you want the directory contents alphabetically sorted without regards to capitalization, you can use:

sorted([f for f in os.listdir('./')], key=lambda f: f.lower())

cle

On Windows, Linux and OS X:

if os.name == 'nt':
    import win32api, win32con


def folder_is_hidden(p):
    if os.name== 'nt':
        attribute = win32api.GetFileAttributes(p)
        return attribute & (win32con.FILE_ATTRIBUTE_HIDDEN | win32con.FILE_ATTRIBUTE_SYSTEM)
    else:
        return p.startswith('.') #linux-osx

filter( lambda f: not f.startswith('.'), os.listdir('.'))

glob:

>>> import glob
>>> glob.glob('*')

(glob claims to use listdir and fnmatch under the hood, but it also checks for a leading '.', not by using fnmatch.)

I think it is too much of work to go through all of the items in a loop. I would prefer something simpler like this:

lst = os.listdir(path)
if '.DS_Store' in lst:
    lst.remove('.DS_Store')

If the directory contains more than one hidden files, then this can help:

all_files = os.popen('ls -1').read()
lst = all_files.split('\n')

filenames = (f.name for f in os.scandir() if not f.name.startswith('.'))

来源：https://stackoverflow.com/questions/7099290/how-to-ignore-hidden-files-using-os-listdir

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python

hidden-files