问题
I'm using Jasmine to test my angular application and want to spy on an anonymous function. Using angular-notify service https://github.com/cgross/angular-notify, I want to know whether notify function have been called or not.
Here is my controller:
angular.module('module').controller('MyCtrl', function($scope, MyService, notify) {
$scope.isValid = function(obj) {
if (!MyService.isNameValid(obj.name)) {
notify({ message:'Name not valid', classes: ['alert'] });
return false;
}
}
});
And here is my test:
'use strict';
describe('Test MyCtrl', function () {
var scope, $location, createController, controller, notify;
beforeEach(module('module'));
beforeEach(inject(function ($rootScope, $controller, _$location_, _notify_) {
$location = _$location_;
scope = $rootScope.$new();
notify = _notify_;
notify = jasmine.createSpy('spy').andReturn('test');
createController = function() {
return $controller('MyCtrl', {
'$scope': scope
});
};
}));
it('should call notify', function() {
spyOn(notify);
controller = createController();
scope.isValid('name');
expect(notify).toHaveBeenCalled();
});
});
An obviously return :
Error: No method name supplied on 'spyOn(notify)'
Because it should be something like spyOn(notify, 'method'), but as it's an anonymous function, it doesn't have any method.
Thanks for your help.
回答1:
Daniel Smink's answer is correct, but note that the syntax has changed for Jasmine 2.0.
notify = jasmine.createSpy().and.callFake(function() {
return false;
});
I also found it useful to just directly return a response if you only need a simple implementation
notify = jasmine.createSpy().and.returnValue(false);
回答2:
You could chain your spy with andCallFake see:
http://jasmine.github.io/1.3/introduction.html#section-Spies:_andCallFake
//create a spy and define it to change notify
notify = jasmine.createSpy().andCallFake(function() {
return false;
});
it('should be a function', function() {
expect(typeof notify).toBe('function');
});
controller = createController();
scope.isValid('name');
expect(notify).toHaveBeenCalled();
来源:https://stackoverflow.com/questions/28580540/how-to-spy-on-anonymous-function-using-jasmine