problem:https://leetcode.com/problems/perfect-squares
数字类dp。查找当前数字减去一个平方数对应的最小拆分次数。
class Solution {
public:
int numSquares(int n) {
vector<int> dp(n + 1, INT_MAX);
dp[0] = 0;
for(int i = 1;i <= n; i++)
{
for(int j = 1;j * j <= i; j++)
{
dp[i] = min(dp[i], dp[i - j * j] + 1);
}
}
return dp[n];
}
};