How do I write a Windows batch script to copy the newest file from a directory?

Question

I need to copy the newest file in a directory to a new location. So far I've found resources on the forfiles command, a date-related question here, and another related question. I'm just having a bit of trouble putting the pieces together! How do I copy the newest file in that directory to a new place?

Answer 1

Windows shell, one liner:

FOR /F %%I IN ('DIR *.* /B /O:-D') DO COPY %%I <<NewDir>> & EXIT

Answer 2

The accepted answer gives an example of using the newest file in a command and then exiting. If you need to do this in a bat file with other complex operations you can use the following to store the file name of the newest file in a variable:

FOR /F "delims=|" %%I IN ('DIR "*.*" /B /O:D') DO SET NewestFile=%%I

Now you can reference %NewestFile% throughout the rest of your bat file.

For example here is what we use to get the latest version of a database .bak file from a directory, copy it to a server, and then restore the db:

:Variables
SET DatabaseBackupPath=\\virtualserver1\Database Backups

echo.
echo Restore WebServer Database
FOR /F "delims=|" %%I IN ('DIR "%DatabaseBackupPath%\WebServer\*.bak" /B /O:D') DO SET NewestFile=%%I
copy "%DatabaseBackupPath%\WebServer\%NewestFile%" "D:\"

sqlcmd -U <username> -P <password> -d master -Q ^
"RESTORE DATABASE [ExampleDatabaseName] ^
FROM  DISK = N'D:\%NewestFile%' ^
WITH  FILE = 1,  ^
MOVE N'Example_CS' TO N'C:\Program Files\Microsoft SQL Server\MSSQL.1\MSSQL\Example.mdf',  ^
MOVE N'Example_CS_log' TO N'C:\Program Files\Microsoft SQL Server\MSSQL.1\MSSQL\Example_1.LDF',  ^
NOUNLOAD,  STATS = 10"

Answer 3

To allow this to work with filenames using spaces, a modified version of the accepted answer is needed:

FOR /F "delims=" %%I IN ('DIR . /B /O:-D') DO COPY "%%I" <<NewDir>> & GOTO :END
:END

Answer 4

@Chris Noe

Note that the space in front of the & becomes part of the previous command. That has bitten me with SET, which happily puts trailing blanks into the value.

To get around the trailing-space being added to an environment variable, wrap the set command in parens.

E.g. FOR /F %%I IN ('DIR "*.*" /B /O:D') DO (SET NewestFile=%%I)

Answer 5

I know you asked for Windows but thought I'd add this anyway,in Unix/Linux you could do:

cp `ls -t1 | head -1` /somedir/

Which will list all files in the current directory sorted by modification time and then cp the most recent to /somedir/

Answer 6

This will open a second cmd.exe window. If you want it to go away, replace the /K with /C.

Obviously, replace new_file_loc with whatever your new file location will be.

@echo off
for /F %%i in ('dir /B /O:-D *.txt') do (
    call :open "%%i"
    exit /B 0
)
:open
    start "window title" "cmd /K copy %~1 new_file_loc"
exit /B 0

Answer 7

@echo off
set source="C:\test case"
set target="C:\Users\Alexander\Desktop\random folder"

FOR /F "delims=" %%I IN ('DIR %source%\*.* /A:-D /O:-D /B') DO COPY %source%\"%%I" %target% & echo %%I & GOTO :END
:END
TIMEOUT 4

My attempt to copy the newest file from a folder

just set your source and target folders and it should work

This one ignores folders, concern itself only with files

Recommed that you choose filetype in the DIR path changing *.* to *.zip for example

TIMEOUT wont work on winXP I think

Answer 8

Bash:

 find -type f -printf "%T@ %p \n" \
     | sort  \
     | tail -n 1  \
     | sed -r "s/^\S+\s//;s/\s*$//" \
     | xargs -iSTR cp STR newestfile

where "newestfile" will become the newestfile

alternatively, you could do newdir/STR or just newdir

Breakdown:

1. list all files in {time} {file} format.
2. sort them by time
3. get the last one
4. cut off the time, and whitespace from the start/end
5. copy resulting value

Important

After running this once, the newest file will be whatever you just copied :p ( assuming they're both in the same search scope that is ). So you may have to adjust which filenumber you copy if you want this to work more than once.