Probability to visit nodes in a random walk on graph

自闭症网瘾萝莉.ら 提交于 2019-12-04 08:41:21

As is often the case with graphs, it's simply a matter of knowing an appropriate way to describe the problem.

One way of writing a graph is as an adjacency matrix. If your graph G = (V, E) has |V| nodes (where |V| is the number of vertices), the this matrix will be |V| x |V|. If an edge exists between a pair of vertices, you set the item in the adjacency matrix to 1, or 0 if it isn't present.

A natural extension of this is to weighted graphs. Here, rather than 0 or 1, the adjacency matrix has some notion of weight.

In the case you're describing, you have a weighted graph where the weights are the probability of transitioning from one node to another. This type of matrix has a special name, it is a stochastic matrix. Depending on how you've arranged your matrix, this matrix will have either rows or columns that sum to 1, right and left stochastic matrices respectively.

One link between stochastic matrices and graphs is Markov Chains. In Markov chain literature the critical thing you need to have is a transition matrix (the adjacency matrix with weights equal to the probability of transition after one time-step). Let's call the transition matrix P.

Working out the probability of transitioning from one state to another after k timesteps is given by P^k. If you have a known source state i, then the i-th row of P^k will give you the probability of transitioning to any other state. This gives you an estimate of the probability of being in a given state in the short term

Depending on your source graph, it may be that P^k reaches a steady state distribution - that is, P^k = P^(k+1) for some value of k. This gives you an estimate of the probability of being in a given state in the long term

As an aside, before you do any of this, you should be able to look at your graph, and say some things about what the probability of being in a given state is at some time.

  1. If your graph has disjoint components, the probability of being in a component that you didn't start in is zero.
  2. If your graph has some states that are absorbing, that is, some states (or groups of states) are inescapable once you've entered them, then you'll need to account for that. This may happen if your graph is tree-like.
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