问题
Given an example of table:
id | item_id | user_id | bid_price
----------------------------------
The task is to select rows with minimum bid_price
for each item_id
in the provided set.
For example: item_id = [1, 2, 3]
- so I need to select up to three (3) rows, having a minimum bid_price
.
Example of data:
id | item_id | user_id | bid_price
----------------------------------
1 | 1 | 11 | 1
2 | 1 | 12 | 2
3 | 1 | 13 | 3
4 | 1 | 14 | 1
5 | 1 | 15 | 4
6 | 2 | 16 | 2
7 | 2 | 17 | 1
8 | 3 | 18 | 2
9 | 3 | 19 | 3
10 | 3 | 18 | 2
Expected result:
id | item_id | user_id | bid_price
----------------------------------
1 | 1 | 11 | 1
7 | 2 | 17 | 1
8 | 3 | 18 | 2
Actually, I'm using Symfony/Docine DQL, but it will be enough with a plain SQL example.
回答1:
For the all the columns in the rows you could use a inner join on subselect for min bid price
select m.id, m.item_id, m.user_id, m.bid_price
from my_table m
inner join (
select item_id, min(id) min_id, min(bid_price) min_price
from my_table
where item_id IN (1,2,3)
group by item_id
) t on t.item_id = m.item_id
and t.min_price= m.bid_price
and t.min_id = m.id
or .. if you have some float data type you could use a acst for unsigned
select m.id, m.item_id, m.user_id, cast(m.bid_price as UNSIGNED)
from my_table m
inner join (
select item_id, min(id) min_id, min(bid_price) min_price
from my_table
where item_id IN (1,2,3)
group by item_id
) t on t.item_id = m.item_id
and t.min_price= m.bid_price
and t.min_id = m.id
回答2:
You can use MIN()
with GROUP BY
in the query:
SELECT id, item_id, MIN(bid_price) AS min_bid, user_id
FROM your_tbl
GROUP BY item_id
HAVING item_id in(1, 2, 3);
回答3:
Use this query:
SELECT id, item_id, user_id, min(bid_price) as bid_price
FROM YOUR_TABLE_NAME
GROUP BY item_id;
来源:https://stackoverflow.com/questions/49490275/stuck-in-building-mysql-query