Read text file into char Array. C++ ifstream

主宰稳场 提交于 2019-12-04 06:33:31

Every time you read a new line you overwrite the old one. Keep an index variable i and use infile.read(getdata+i,1) then increment i.

std::ifstream infile;
infile.open("Textfile.txt", std::ios::binary);
infile.seekg(0, std::ios::end);
size_t file_size_in_byte = infile.tellg();
std::vector<char> data; // used to store text data
data.resize(file_size_in_byte);
infile.seekg(0, std::ios::beg);
infile.read(&data[0], file_size_in_byte);

Use std::string:

std::string contents;

contents.assign(std::istreambuf_iterator<char>(infile),
                std::istreambuf_iterator<char>());

You don't need to read line by line if you're planning to suck the entire file into a buffer.

char getdata[10000];
infile.read(getdata, sizeof getdata);
if (infile.eof())
{
    // got the whole file...
    size_t bytes_really_read = infile.gcount();

}
else if (infile.fail())
{
    // some other error...
}
else
{
    // getdata must be full, but the file is larger...

}

You could use Tony Delroy's answer and incorporate a little function to determine the size of the file, and then create the char array of that size, like this:

//Code from Andro in the following question: https://stackoverflow.com/questions/5840148/how-can-i-get-a-files-size-in-c

int getFileSize(std::string filename) { // path to file
    FILE *p_file = NULL;
    p_file = fopen(filename.c_str(),"rb");
    fseek(p_file,0,SEEK_END);
    int size = ftell(p_file);
    fclose(p_file);
    return size;
}

Then you can do this:

//Edited Code From Tony Delroy's Answer
char getdata[getFileSize("file.txt")];
infile.read(getdata, sizeof getdata);

if (infile.eof()) {
    // got the whole file...
    size_t bytes_really_read = infile.gcount();
}
else if (infile.fail()) {
    // some other error...
}
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