How to create nested list from PHP array for dropdown select field?

柔情痞子 提交于 2019-12-04 05:33:55

问题


My problem is very similar to the one described here in this topic Create nested list from PHP array for dropdown select field The problem is that if investments are not consecutive, then incorrectly adds a dash

function buildTree(Array $data, $parent = 0) {
    $tree = array();
    foreach ($data as $d) {
        if ($d['parent'] == $parent) {
            $children = buildTree($data, $d['id']);
            // set a trivial key
            if (!empty($children)) {
                $d['_children'] = $children;
            }
            $tree[] = $d;
        }
    }
    return $tree;
}

function printTree($tree, $r = 0, $p = null) {
    foreach ($tree as $i => $t) {
        $dash = ($t['parent'] == 0) ? '' : str_repeat('-', $r) .' ';
        printf("\t<option value='%d'>%s%s</option>\n", $t['id'], $dash, $t['name']);
        if ($t['parent'] == $p) {
            // reset $r
            $r = 0;
        }
        if (isset($t['_children'])) {
            printTree($t['_children'], ++$r, $t['parent']);
        }
    }
}

This solution works for such a structure array

$rows = array(
    array ('id' => 1, 'name' => 'Test 1', 'parent' => 0),
    array ('id' => 2, 'name' => 'Test 1.1', 'parent' => 1),
    array ('id' => 3, 'name' => 'Test 1.2', 'parent' => 1),
    array ('id' => 4, 'name' => 'Test 1.2.1', 'parent' => 3),
    array ('id' => 5, 'name' => 'Test 1.2.2', 'parent' => 3),
    array ('id' => 6, 'name' => 'Test 1.2.2.1', 'parent' => 5),
    array ('id' => 7, 'name' => 'Test 2', 'parent' => 0),
    array ('id' => 8, 'name' => 'Test 2.1', 'parent' => 7),
);

But does not work for this

$rows = array(
    array ('id' => 1, 'name' => 'Test 1', 'parent' => 0),
    array ('id' => 2, 'name' => 'Test 1.1', 'parent' => 1),
    array ('id' => 3, 'name' => 'Test 1.2', 'parent' => 1),
    array ('id' => 4, 'name' => 'Test 1.2.1', 'parent' => 3),
    array ('id' => 5, 'name' => 'Test 1.2.2', 'parent' => 3),
    array ('id' => 6, 'name' => 'Test 1.2.2.1', 'parent' => 5),
    array ('id' => 7, 'name' => 'Test 2', 'parent' => 0),
    array ('id' => 8, 'name' => 'Test 2.1', 'parent' => 1),
    array ('id' => 9, 'name' => 'another data', 'parent' => 1),
);

How can I change it? sorry for my english


回答1:


It does not work because you are not setting the "parent" attribute right. Even if the name is "Test 2.1", using this algorithm, you have to set the parent index. If you change your array to this, it'll work:

$rows = array(
    array ('id' => 1, 'name' => 'Test 1', 'parent' => 0),
    array ('id' => 2, 'name' => 'Test 1.1', 'parent' => 1),
    array ('id' => 3, 'name' => 'Test 1.2', 'parent' => 1),
    array ('id' => 4, 'name' => 'Test 1.2.1', 'parent' => 3),
    array ('id' => 5, 'name' => 'Test 1.2.2', 'parent' => 3),
    array ('id' => 6, 'name' => 'Test 1.2.2.1', 'parent' => 5),
    array ('id' => 7, 'name' => 'Test 2', 'parent' => 0),
    array ('id' => 8, 'name' => 'Test 2.1', 'parent' => 7),
    array ('id' => 9, 'name' => 'another data with no parent', 'parent' => 0),
);



回答2:


I just solved your problem here on SO in another question

just replace ++$r with $r+1

the "dash" now works great.



来源:https://stackoverflow.com/questions/18252529/how-to-create-nested-list-from-php-array-for-dropdown-select-field

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