How to get Device UDID in programmatically in iOS7?

问题

How to get device UDID in programatically in iOS7.[[UIDevice currentDevice] uniqueIdentifier] I was used this code This is deprecated iOS7. how to get the device UDID. The UDID String changing when I delete the app and the reinstall means the UDID was getting different one.

回答1:

It's work 100% to all the version

other best option recommend by apple use ASIdentifierManager Class Reference

ios7-app-backward-compatible-with-ios5-regarding-unique-identifier

this link tell you how to handle and use custom framework

uidevice-uniqueidentifier-property-is-deprecated-what-now

iOS 9

NSUUID *uuid = [[NSUUID alloc]initWithUUIDString:@"20B0DDE7-6087-4607-842A-E97C72E4D522"];
NSLog(@"%@",uuid);
NSLog(@"%@",[uuid UUIDString]);

it support only ios 6.0 and above

code to use [[[UIDevice currentDevice] identifierForVendor] UUIDString];

NSUUID *deviceId;
#if TARGET_IPHONE_SIMULATOR
deviceId = [NSUUID initWithUUIDString:@"UUID-STRING-VALUE"];
#else
deviceId = [UIDevice currentDevice].identifierForVendor;
#endif

ios 5 to use like

 if ([[UIDevice currentDevice] respondsToSelector:@selector(identifierForVendor)]) {
    // This is will run if it is iOS6
    return [[[UIDevice currentDevice] identifierForVendor] UUIDString];
} else {
   // This is will run before iOS6 and you can use openUDID or other 
   // method to generate an identifier
}

回答2:

UDID is no longer available in iOS 6+ due to security / privacy reasons. Instead, use identifierForVendor or advertisingIdentifier.

Please go through this link.

   NSString* uniqueIdentifier = [[[UIDevice currentDevice] identifierForVendor] UUIDString]; // IOS 6+
   NSLog(@"UDID:: %@", uniqueIdentifier);

UPDATE for iOS 8+

+ (NSString *)deviceUUID
{
    if([[NSUserDefaults standardUserDefaults] objectForKey:[[NSBundle mainBundle] bundleIdentifier]])
        return [[NSUserDefaults standardUserDefaults] objectForKey:[[NSBundle mainBundle] bundleIdentifier]];

    @autoreleasepool {

        CFUUIDRef uuidReference = CFUUIDCreate(nil);
        CFStringRef stringReference = CFUUIDCreateString(nil, uuidReference);
        NSString *uuidString = (__bridge NSString *)(stringReference);
        [[NSUserDefaults standardUserDefaults] setObject:uuidString forKey:[[NSBundle mainBundle] bundleIdentifier]];
        [[NSUserDefaults standardUserDefaults] synchronize];
        CFRelease(uuidReference);
        CFRelease(stringReference);
        return uuidString;
    }
}

回答3:

In Swift you can get the device UUID like this

let uuid = UIDevice.currentDevice().identifierForVendor.UUIDString
println(uuid)

回答4:

Use identifierForVendor or advertisingIdentifier.

identifierForVendor:

An alphanumeric string that uniquely identifies a device to the app’s vendor. (read-only)

The value of this property is the same for apps that come from the same vendor running on the same device. A different value is returned for apps on the same device that come from different vendors, and for apps on different devices regardless of vendor.

advertisingIdentifier:

An alphanumeric string unique to each device, used only for serving advertisements. (read-only)

Unlike the identifierForVendor property of UIDevice, the same value is returned to all vendors. This identifier may change—for example, if the user erases the device—so you should not cache it.

Also, see Apple's documentation for the identifierForVendor and advertisingIdentifier.

回答5:

In iOS 7, Apple now always returns a fixed value when querying the MAC to specifically thwart the MAC as base for an ID scheme. So you now really should use -[UIDevice identifierForVendor] or create a per-install UUID.

Check this SO Question.

回答6:

In Swift 3.0:

UIDevice.current.identifierForVendor!.uuidString

old version

UIDevice.currentDevice().identifierForVendor

you want a string:

UIDevice.currentDevice().identifierForVendor!.UUIDString

回答7:

For getting UDID: (If you're using this Might be App store guys won't allow it --> As per my concern)

- (NSString *)udid
{
void *gestalt = dlopen("/usr/lib/libMobileGestalt.dylib", RTLD_GLOBAL | RTLD_LAZY);
CFStringRef (*MGCopyAnswer)(CFStringRef) = (CFStringRef (*)(CFStringRef))(dlsym(gestalt, "MGCopyAnswer"));
return CFBridgingRelease(MGCopyAnswer(CFSTR("UniqueDeviceID")));
}

 **Entitlements:**
 <key>com.apple.private.MobileGestalt.AllowedProtectedKeys</key>
   <array>
<string>UniqueDeviceID</string>
</array>

For Getting UUID:

    self.uuidTxtFldRef.text = [[[UIDevice currentDevice] identifierForVendor] UUIDString];

回答8:

Swift 2.2+ proper way to get UUID:

if let UUID = UIDevice.currentDevice().identifierForVendor {
  print("UUID: \(UUID.UUIDString)")
}

回答9:

Have 2 solutions:

You can use identifierForVendor after that store them to keychain and use later. Because value of keychain will not changed when re-install app.
You can try OpenUDID

回答10:

For getting UUID in Swift 3.0:

let UUIDValue = UIDevice.current.identifierForVendor!.uuidString

来源：https://stackoverflow.com/questions/20944932/how-to-get-device-udid-in-programmatically-in-ios7

标签

iphone

udid