Sorting 'numbers' with multiple decimal points

前提是你 提交于 2019-12-04 00:35:55

问题


I've got a bunch of "numbers" that have multiple decimal points (so they're really strings). However, I want to sort them as if they were numbers.

1.1.1
10.2.3
2.6.7
21.10.4
3.10.12
4.11.5
4.1.16
6.4.23

I want them to sort by the first set of numbers (before the first decimal point), then by the second set, then by the third (with the possibility of it continuing for a fourth set or more). They should go in this order:

1.1.1
2.6.7
3.10.12
4.1.16
4.11.5
6.4.23
10.2.3
21.10.4

What is the best way to do this using JS? I'm thinking I'll probably need to break each number into an array, but there maybe a better way. Ideas?


回答1:


I think something like this should do the trick:

nums.sort(function(a, b) {
    var nums1 = a.split(".");
    var nums2 = b.split(".");

    for (var i = 0; i < nums1.length; i++) {
        if (nums2[i]) { // assuming 5..2 is invalid
            if (nums1[i] !== nums2[i]) {
               return nums1[i] - nums2[i];   
            } // else continue
        } else {
            return 1; // no second number in b
        }
    }
    return -1; // was missing case b.len > a.len
});

Update heres a fiddle

When var nums = ['1.1.1', '2.6.7.3.2', '2.6.7', '2.6.7.3', '2.6.7.1', '6.4.23', '2.7']

Sorting this way => ['1.1.1','2.6.7.1','2.6.7.3.2','2.6.7','2.6.7.3','2.7','6.4.23']




回答2:


To please megawac :D

list.sort(function (a, b) {
    var result;
    a = a.split('.');
    b = b.split('.');
    while (a.length) {
        if (result = a.shift() - (b.shift() || 0)) {
            return result;
        }
    }
    return -b.length;
});

Handles any number of dots :

input  ['1.3', '10', '1.2', '2', '1.1.2', '1.1.1', '1.1']
output ['1.1', '1.1.1', '1.1.2', '1.2', '1.3', '2', '10']



回答3:


Try this :

var list = ['1.1.1', '10.2.3', '2.6.7', '21.10.4', '3.10.12', '4.11.5', '4.1.16', '6.4.23'];

list.sort(function (a, b) {
    a = a.split('.');
    b = b.split('.');
    return (
        a.shift() - b.shift()
    ) || (
        a.shift() - b.shift()
    ) || (
        a.shift() - b.shift()
    );
});



回答4:


I went about this by splitting each number into an array and then performing a multidimensional sort, using a custom sort method. Here's what I've got:

function multiDecimalSort(input) {
    var output,
        i,
        len;

    output = [];

    // Unglue decimal parts
    for (i = 0, len = input.length; i < len; i++) {
        output.push(input[i].split('.'));
    }

    // Apply custom sort
    output.sort(function (a, b) {
        for (i = 0, len = a.length; i < len; i++) {
            // cast decimal part to int
            a[i] = parseInt(a[i], 10);
            b[i] = parseInt(b[i], 10);

            if (a[i] !== b[i]) {
                return a[i] - b[i];
            }
        }
    });

    // Rejoin decimal parts
    for (i = 0, len = input.length; i < len; i++) {
        output[i] = output[i].join(".");
    }

    return output;
}


来源:https://stackoverflow.com/questions/20080393/sorting-numbers-with-multiple-decimal-points

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!