Hey guys, I'm getting the above warning when I try to run this code:
$mysqli=new mysqli("localhost", "***", "***","***") or die(mysql_error());
function checklogin($username, $password){
global $mysqli;
$result = $mysqli->prepare("SELECT * FROM users WHERE username = ?");
$result->bind_param("s", $username);
$result->execute();
if($result != false){
$dbArray=mysql_fetch_array($result);
You are mixing mysql and mysqli calls in your code. Use mysqli_fetch_array instead of mysql_fetch_array.
You are mixing mysqli and traditional mysql commands.
You're using two different sets of functions... mysqli and mysql.
I think you want to use the fetch_assoc() method.
Check out http://php.net/manual/en/book.mysqli.php
来源:https://stackoverflow.com/questions/4635007/warningmysql-fetch-array-expects-parameter-1-to-be-resource-object-given