Double click to Windows form in C#

Question

How can I detect, which mouse button have double clicked the form i.e. Left, Right or Middle?

Updated: I am using .NET2.0

Answer 1

Store the last clicked button in MouseUp event and then check that in the double click event. Sample code:

MouseButtons _lastButtonUp = MouseButtons.None;

private void Form1_MouseUp(object sender, MouseEventArgs e)
{
    _lastButtonUp = e.Button;
}

private void Form1_DoubleClick(object sender, EventArgs e)
{
    switch (_lastButtonUp)
    {
        case System.Windows.Forms.MouseButtons.Left:
            MessageBox.Show("left double click");
            break;
        case System.Windows.Forms.MouseButtons.Right:
            MessageBox.Show("right double click");
            break;
        case System.Windows.Forms.MouseButtons.Middle:
            MessageBox.Show("middle double click");
            break;
    }

}

Answer 2

Have a look at MouseDoubleClick and MouseEventArgs and MouseButtons Enumeration

MouseDoubleClick is one of the Form events.

Answer 3

In Whatever_Click or DoubleClick event, you can check the MouseEventArgs e, which contains what key was pressed.

 private void Form1_MouseDoubleClick(object sender, MouseEventArgs e)
 {
    if (e.Button == MouseButtons.Left)
       Console.WriteLine("Left Mouse Button was clicked!");
    else if (e.Button == MouseButtons.Middle)
       Console.WriteLine("Middle Mouse Button was clicked!");
 } 

Other buttons include MouseButtons.Right, MouseButtons.Left

Answer 4

in form_MouseDoubleClick event you can trace

void Form1_MouseDoubleClick(object sender, MouseEventArgs e)
 {
    if (e.Button == MouseButtons.Left)
       {
            // Do Operation
       }
 }