How to write 'n' copies of a character to ostream like in python

问题

In python, the following instruction: print 'a'*5 would output aaaaa. How would one write something similar in C++ in conjunction with std::ostreams in order to avoid a for construct?

回答1:

The obvious way would be with fill_n:

std::fill_n(std::ostream_iterator<char>(std::cout), 5, 'a');

Another possibility would be be to just construct a string:

std:cout << std::string(5, 'a');

回答2:

Use some tricky way: os << setw(n) << setfill(c) << ""; Where n is number of char c to write

回答3:

You can do something like that by overloading the * operator for std::string. Here is a small example

#include<iostream>
#include<string>
std::string operator*(const std::string &c,int n)
{
    std::string str;
    for(int i=0;i<n;i++)
    str+=c;
    return str;
}
int main()
{
    std::string str= "foo";
    std::cout<< str*5 <<"\n";
}

来源：https://stackoverflow.com/questions/11421632/how-to-write-n-copies-of-a-character-to-ostream-like-in-python