How do I dynamically build an ng-include src?

半城伤御伤魂 提交于 2019-12-03 14:40:36

问题


I have the following code:

<div ng-repeat="module in modules" id="{{module.Id}}">
    <ng-include ng-init="bootstrapModule(module.Id)" src=""></ng-include>
</div>

I want to be able to build a string in src like so:

/modules/{{module.Name}}/{{module.Name}}.tpl.html

But I keep hitting roadblocks. I've tried to use a call back function to build it,

$scope.constructTemplateUrl = function(id) {
    return '/modules/' + id + '/' + id + '.tpl.html';
}

But this gets called over & over & over and it doesn't seem to like that. I've also tried to construct it like so:

ng-src="/modules/{{module.Id}}/{{module.Id}}.tpl.html"

But that isn't working either. Rather than spend hours beating around the bush, I wondered if anyone else has come up against something like this and has any ideas?

Also, when I grab the modules from $resource, I am returning them asynchronously with $q, so I can't seem to go through and add it into the modules before in the controller as $scope.modules just equals a then function at that point.

Any ideas?


回答1:


ngInclude | src directive requires an angular expression, which means you should probably write

ng-src="'/modules/' + module.Id + '/tpl.html'"

From http://docs.angularjs.org/api/ng.directive:ngInclude

ngInclude|src string angular expression evaluating to URL. If the source is a string constant, make sure you wrap it in quotes, e.g. src="'myPartialTemplate.html'".

It might be better if you construct the url in model instead of inline HTML

<div ng-repeat="module in modules" id="{{module.Id}}">
    <ng-include src="module.url"></ng-include>
</div>


来源:https://stackoverflow.com/questions/18976255/how-do-i-dynamically-build-an-ng-include-src

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!