Display multiple 2D plots in 3D using Graphics in Mathematica?

一曲冷凌霜 提交于 2019-12-03 14:02:17

问题


Considering the following :

lalist = {{{{1, 1}, 1}, {{3, 3}, 1}, {{5, 5}, 1}},
          {{{1, 5}, 1}, {{3, 3}, 1}, {{5, 1}, 1}}}

Row[{
  Graphics[{
            Opacity[0.5],Red, 
            Disk @@@ lalist[[1]]}, 
            Frame -> True],
  Graphics[{
            Opacity[0.5],Blue, 
            Disk @@@ lalist[[2]]}, 
            Frame -> True]}
    ]

  • Is it possible that I plot the Blues Disks "behind" the red ones in a 3 D plot ?

Below is not what I need :


回答1:


Like this?

Graphics3D[{{Texture[
 Graphics[{Opacity[0.5], Blue, Disk @@@ lalist[[2]]}, 
  Frame -> True]], 
 Polygon[{{-1, -1, -1}, {1, -1, -1}, {1, 1, -1}, {-1, 1, -1}}, 
 VertexTextureCoordinates \[Rule] {{0, 0}, {1, 0}, {1, 1}, {0, 
    1}}]}, {Texture[
 Graphics[{Opacity[0.5], Red, Disk @@@ lalist[[1]]}, 
  Frame -> True]], 
Polygon[{{-1, -1, 1}, {1, -1, 1}, {1, 1, 1}, {-1, 1, 1}}, 
 VertexTextureCoordinates \[Rule] {{0, 0}, {1, 0}, {1, 1}, {0, 
    1}}]}}, Lighting \[Rule] "Neutral"]

Lots of them with opacity .2:

tab = Table[{Opacity \[Rule] .2, 
Texture[Graphics[{Opacity[0.5], Blue, Disk @@@ lalist[[2]]}, 
  Frame -> True]], 
Polygon[{{-1, -1, z}, {1, -1, z}, {1, 1, z}, {-1, 1, z}}, 
 VertexTextureCoordinates \[Rule] {{0, 0}, {1, 0}, {1, 1}, {0, 
    1}}]}, {z, -2, 2, 1}];
plt = Graphics3D[{tab}, Lighting \[Rule] "Neutral"]

and 400 don't seem to be much of a problem in terms of speed (you can easily modify the code above to see it).

EDIT: OK, just to be silly, try this

Dynamic[Graphics3D[{{Texture[#], 
  Polygon[{{-1, -1, -1}, {1, -1, -1}, {1, 1, -1}, {-1, 1, -1}}, 
   VertexTextureCoordinates \[Rule] {{0, 0}, {1, 0}, {1, 1}, {0, 
      1}}]}, {Texture[Rotate[#, \[Pi]/2]], 
  Polygon[{{-1, -1, 1}, {1, -1, 1}, {1, 1, 1}, {-1, 1, 1}}, 
   VertexTextureCoordinates \[Rule] {{0, 0}, {1, 0}, {1, 1}, {0, 
      1}}]}}, Lighting \[Rule] "Neutral"] &@Binarize[CurrentImage[]]]

which gives

(or something like that), rotatable, updated in real time etc.




回答2:


See the solution presented on "Lunchtime Playground: Fun with Mathematica" here: http://mathgis.blogspot.com/2009/02/howto-display-2d-plot-in-3d.html




回答3:


Using transparent textures to render these circles in layers as ACL does is a nice solution, unless one wants to interact with the resulting 3D object. Rendering of 3D objects that contain transparent elements is done in software whereas otherwise it would have been done in hardware:

The 3D renderer uses two different methods of sorting polygons. For graphics scenes that include no transparency, a hardware-accelerated depth buffer is used. Otherwise, the renderer uses a binary space partition tree to split and sort polygons from any viewpoint. The BSP tree is slower to create and is not hardware accelerated, but it provides the most general ability to support polygons.

On my laptop, interaction with 3D graphics is incredibly slow as soon as transparent objects start to appear.

The solution would be to use 3D disks instead of semi transparent planes with 2D disks in them. Since MMA doesn't have 3D Disks or Circles if you want to do something like that, you have to roll your own. A bare-bones version would be something like:

myDisk[{x_, y_, z_}, r_] := 
 Polygon@Table[
               {x, y, z} + r {Cos[\[Phi]], Sin[\[Phi]], 0} // N,
               {\[Phi], 0, 2 \[Pi], 2 \[Pi]/200}
              ]

Your layers would then be generated as follows:

Graphics3D[
 {
   EdgeForm[],
  {
   Red, 
   myDisk[{1, 1, 0.5}, 0.5],  
   myDisk[{0, 0, 0.5}, 0.5],   
   myDisk[{-1, -1, 0.5}, 0.5]
  },
  {
   Blue,  
   myDisk[{1, -1, -0.5}, 0.5],
   myDisk[{0, 0, -0.5}, -0.5], 
   myDisk[{-1, 1, -0.5}, 0.5]}
  }
 ]



来源:https://stackoverflow.com/questions/6486907/display-multiple-2d-plots-in-3d-using-graphics-in-mathematica

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!