Ruby/Rails 3.1: Given a URL string, remove path

Question

Given any valid HTTP/HTTPS string, I would like to parse/transform it such that the end result is exactly the root of the string.

So given URLs:

http://foo.example.com:8080/whatsit/foo.bar?x=y
https://example.net/

I would like the results:

http://foo.example.com:8080/
https://example.net/

I found the documentation for URI::Parser not super approachable.

My initial, naïve solution would be a simple regex like:

/\A(https?:\/\/[^\/]+\/)/

(That is: Match up to the first slash after the protocol.)

Thoughts & solutions welcome. And apologies if this is a duplicate, but my search results weren't relevant.

Answer 1

With URI::join:

require 'uri'
url = "http://foo.example.com:8080/whatsit/foo.bar?x=y"
baseurl = URI.join(url, "/").to_s
#=> "http://foo.example.com:8080/"

Answer 2

Use URI.parse and then set the path to an empty string and the query to nil:

require 'uri'
uri     = URI.parse('http://foo.example.com:8080/whatsit/foo.bar?x=y')
uri.path  = ''
uri.query = nil
cleaned   = uri.to_s # http://foo.example.com:8080

Now you have your cleaned up version in cleaned. Taking out what you don't want is sometimes easier than only grabbing what you need.

If you only do uri.query = '' you'll end up with http://foo.example.com:8080? which probably isn't what you want.

Answer 3

You could use uri.split() and then put the parts back together...

WARNING: It's a little sloppy.

url = "http://example.com:9001/over-nine-thousand"
parts = uri.split(url)
puts "%s://%s:%s" % [parts[0], parts[2], parts[3]]

=> "http://example.com:9001"