C# - DatagridView and ContextMenu

寵の児 提交于 2019-12-03 12:40:20

Try this

 private void dataGridView1_CellMouseDown(object sender, MouseEventArgs e)
{
  if (e.Button == MouseButtons.Right)
  {
        contextMenu.Show(datagridview, e.Location);
  }

} 

or

 private void dataGridView_MouseUp(object sender, MouseEventArgs e)
 {
   // Load context menu on right mouse click
   DataGridView.HitTestInfo hitTestInfo;
   if (e.Button == MouseButtons.Right)
   {
      hitTestInfo = dataGridView.HitTest(e.X, e.Y);
      // If column is first column
      if (hitTestInfo.Type == DataGridViewHitTestType.Cell && hitTestInfo.ColumnIndex == 0)
        contextMenuForColumn1.Show(dataGridView, new Point(e.X, e.Y));
    // If column is second column
      if (hitTestInfo.Type == DataGridViewHitTestType.Cell && hitTestInfo.ColumnIndex == 1)
        contextMenuForColumn2.Show(dataGridView, new Point(e.X, e.Y));
   }
} 
CHARNICHARTLG

For the problem with the relative position, you can also use this aproach:

DataGridViewColumn dgvC = new DataGridViewColumn();
DataGridViewRow dgvR = new DataGridViewRow();
dgvC = dgv.Columns[e.ColumnIndex];
dgvR = dgv.Rows[e.RowIndex];
Point p = new Point();
p.X = (dgvC.Width * e.ColumnIndex) + e.X;
p.Y = (dgvR.Height * e.RowIndex) + e.Y;
dgv.ContextMenu.Show(dgv, p);
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