Define Servlet Context in WAR-File

问题

How can I tell e.g. Tomcat to use a specific context path when given my WAR-File?

Example: I have a war file created by maven build and the resulting name of the file is rather long. So I do not want the tomcat manager application to use the filename of the war as the context.

Supplying a context.xml in META-INF did not produce the desired results

I also found this in the documentation for the path attribute of Context:

The value of this field must not be set except when statically defining a Context in server.xml, as it will be inferred from the filenames used for either the .xml context file or the docBase.

So it does not seem to be the right way to tell the application-server what the path for my WAR should be.

Any more hints?

回答1:

There are two important points in the the documentation of the Context Container:

In individual files (with a ".xml" extension) in the $CATALINA_BASE/conf/[enginename]/[hostname]/ directory. The name of the file (less the .xml extension) will be used as the context path. Multi-level context paths may be defined using #, e.g. foo#bar.xml for a context path of /foo/bar. The default web application may be defined by using a file called ROOT.xml.

Only if a context file does not exist for the application in the $CATALINA_BASE/conf/[enginename]/[hostname]/, in an individual file at /META-INF/context.xml inside the application files. If the web application is packaged as a WAR then /META-INF/context.xml will be copied to $CATALINA_BASE/conf/[enginename]/[hostname]/ and renamed to match the application's context path. Once this file exists, it will not be replaced if a new WAR with a newer /META-INF/context.xml is placed in the host's appBase.

So, when you bundle a META-INF/context.xml, the file gets renamed to the name of the WAR and this name becomes the context path, regardless of any path defined in the Context element.

I see thus two options here:

Either set the name of the generated war to a shorter name (I suggest using <finalName> over <warName> which is deprecated AFAIK):
```
<project>
  ...
  <build>
    <finalName>mycontext</finalName>
    ...
  </build>
  ...
</project>
```

Or use the maven-tomcat-plugin for the deployment and set the context path in the plugin configuration:

<project>
  ...
  <build>
    ...
    <plugins>
      ...
      <plugin>
        <groupId>org.codehaus.mojo</groupId>
        <artifactId>tomcat-maven-plugin</artifactId>
        <version>1.0-SNAPSHOT</version>
        <configuration>
          <path>/mycontext</path>
        </configuration>
      </plugin>
      ...
    </plugins>
    ...
  </build>
  ...
</project>

回答2:

I found an easy solution to keep war file name and choose the context-path.

You just have to deploy your war outside of the Host's appBase and to create a link inside the appBase directory.

Ex. :

ln -sf ${CATALINA_HOME}/wars/myapp-0.0.8-SNAPSHOT.war ${CATALINA_HOME}/webapps/myapp.war

Ektor

回答3:

You can set the path attribute of the <Context> element of your META-INF/context.xml.

Alternatively, you can configure maven to create the war artifact with a custom name:

<build>
    <plugins>
         <plugin>
            <artifactId>maven-war-plugin</artifactId>
            <version>2.0</version>
            <configuration>
                <warName>yourCustomWarName</warName>
            </configuration>
        </plugin>
        ........
    </plugins>
</build>

回答4:

In your project there is a folder META-INF, in that folder there is a context.xml file.

<?xml version="1.0" encoding="UTF-8"?>
<Context  path="/myproject" />

来源：https://stackoverflow.com/questions/2593472/define-servlet-context-in-war-file

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java

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tomcat6