Codeforces 1146E Hot is Cold 线段树

Hot is Cold

好像我写麻烦了， 其实只用线段树维护区间每个数反转， 区间赋值就可以。

#include<bits/stdc++.h>
using namespace std;

const int N = (int)1e5 + 7;

int n, q, pos, a[N];
char op[N];

struct Bit {
    int a[N];
    void modify(int x, int v) {
        for(int i = x; i < N; i += i & -i) {
            a[i] += v;
        }
    }
    int query(int x) {
        int ans = 0;
        for(int i = x; i; i -= i & -i) {
            ans += a[i];
        }
        return ans;
    }
} bit;

#define lson l, mid, rt << 1
#define rson mid + 1, r, rt << 1 | 1
struct SegmentTree {
    int a[N << 2], lazy[N << 2], flip[N << 2];
    inline void push(int rt) {
        if(lazy[rt]) {
            a[rt << 1] = lazy[rt];
            a[rt << 1 | 1] = lazy[rt];
            lazy[rt << 1] = lazy[rt];
            flip[rt << 1] = 0;
            lazy[rt << 1 | 1] = lazy[rt];
            flip[rt << 1 | 1] = 0;
            lazy[rt] = 0;
        }
        if(flip[rt]) {
            a[rt << 1] = -a[rt << 1];
            a[rt << 1 | 1] = -a[rt << 1 | 1];
            if(lazy[rt << 1]) lazy[rt << 1] = -lazy[rt << 1];
            else flip[rt << 1] ^= 1;
            if(lazy[rt << 1 | 1]) lazy[rt << 1 | 1] = -lazy[rt << 1 | 1];
            else flip[rt << 1 | 1] ^= 1;
            flip[rt] = 0;
        }
    }
    void update(int L, int R, int val, int l, int r, int rt) {
        if(R < l || r < L || R < L) return;
        if(L <= l && r <= R) {
            a[rt] = val;
            lazy[rt] = val;
            flip[rt] = 0;
            return;
        }
        push(rt);
        int mid = l + r >> 1;
        update(L, R, val, lson);
        update(L, R, val, rson);
    }
    void update2(int L, int R, int l, int r, int rt) {
        if(R < l || r < L || R < L) return;
        if(L <= l && r <= R) {
            a[rt] = -a[rt];
            if(lazy[rt]) lazy[rt] = -lazy[rt];
            else flip[rt] ^= 1;
            return;
        }
        push(rt);
        int mid = l + r >> 1;
        update2(L, R, lson);
        update2(L, R, rson);
    }
    int query(int p, int l, int r, int rt) {
        if(l == r) return a[rt];
        push(rt);
        int mid = l + r >> 1;
        if(p <= mid) return query(p, lson);
        else return query(p, rson);
    }
} Tree;

void show() {
    for(int i = 1; i <= n; i++) {
        int ans = 0;
        if(a[i] != 0) {
            if(abs(a[i]) > pos) ans = abs(a[i]) * Tree.query(abs(a[i]), 0, 100000, 1);
            else ans = (bit.query(abs(a[i])) & 1) ? -a[i] : a[i];
        }
        printf("%d%c", ans, " \n"[i == n]);
    }
}

int main() {
    scanf("%d%d", &n, &q);
    for(int i = 1; i <= n; i++) scanf("%d", &a[i]);
    pos = 100000;
    while(q--) {
        int x;
        scanf("%s%d", op, &x);
        if(*op == '>') {
            if(x >= 0) {
                pos = min(pos, x);
                Tree.update(x + 1, 100000, -1, 0, 100000, 1);
            }
            else {
                pos = min(pos, -x - 1);
                Tree.update(-x, 100000, -1, 0, 100000, 1);
                Tree.update2(1, -x - 1, 0, 100000, 1);
                bit.modify(1, 1);
                bit.modify(-x, -1);
            }
        }
        else {
            if(x <= 0) {
                pos = min(pos, -x);
                Tree.update(-x + 1, 100000, 1, 0, 100000, 1);
            }
            else {
                pos = min(pos, x - 1);
                Tree.update(x, 100000, 1, 0, 100000, 1);
                Tree.update2(1, x - 1, 0, 100000, 1);
                bit.modify(1, 1);
                bit.modify(x, -1);
            }
        }
    }
    show();
    return 0;
}

/*
*/

 

来源：https://www.cnblogs.com/CJLHY/p/11791682.html