问题
When user tap on a universal link in WKWebView, the corresponding app will be opened (if installed).
This is described in Apple Search Programming Guide
If you instantiate a SFSafariViewController, WKWebView, or UIWebView object to handle a universal link, iOS opens your website in Safari instead of opening your app. However, if the user taps a universal link from within an embedded SFSafariViewController, WKWebView, or UIWebView object, iOS opens your app.
In my app, I have a WKWebView, but I don't want the user to go out of my app. I want to handle the link within my WKWebView.
How do I prevent universal link from opening? Or can I know if a URL could be handle by other apps?
回答1:
sourcecode for WebKit:
static const WKNavigationActionPolicy WK_API_AVAILABLE(macosx(10.11), ios(9.0)) _WKNavigationActionPolicyAllowWithoutTryingAppLink = (WKNavigationActionPolicy)(WKNavigationActionPolicyAllow + 2);
if you are using WKWebView, just use WKNavigationActionPolicyAllow + 2 instead of WKNavigationActionPolicyAllow
回答2:
Base on @none 's answer, here is an example for Swift 4
I've tested it and it does work!
func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
decisionHandler(WKNavigationActionPolicy(rawValue: WKNavigationActionPolicy.allow.rawValue + 2)!)
}
回答3:
+[LSAppLink openWithURL:completionHandler:] this is how universal link open corresponding app. you can exchange its implementations with yourself method but be carefule,this is private API.
you can check LSAppLink head file here
回答4:
Can you try this?
func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
decisionHandler(WKNavigationActionPolicy(rawValue: WKNavigationActionPolicy.allow.rawValue + 2)!)
}
来源：https://stackoverflow.com/questions/38450586/prevent-universal-links-from-opening-in-wkwebview-uiwebview