how to get the child node in div using javascript

核能气质少年 提交于 2019-12-03 09:27:00
var tds = document.getElementById("ctl00_ContentPlaceHolder1_Jobs_dlItems_ctl01_a").getElementsByTagName("td");
time = tds[0].firstChild.value;
address = tds[3].firstChild.value;

If you give your table a unique id, its easier:

<div id="ctl00_ContentPlaceHolder1_Jobs_dlItems_ctl01_a"
    onmouseup="checkMultipleSelection(this,event);">
       <table id="ctl00_ContentPlaceHolder1_Jobs_dlItems_ctl01_a_table" 
              cellpadding="0" cellspacing="0" border="0" width="100%">
           <tr>
              <td style="width:50px; text-align:left;">09:15 AM</td>
              <td style="width:50px; text-align:left;">Item001</td>
              <td style="width:50px; text-align:left;">10</td>
              <td style="width:50px; text-align:left;">Address1</td>
              <td style="width:50px; text-align:left;">46545465</td>
              <td style="width:50px; text-align:left;">ref1</td>
           </tr>
       </table>
</div>


var multiselect = 
    document.getElementById(
               'ctl00_ContentPlaceHolder1_Jobs_dlItems_ctl01_a_table'
            ).rows[0].cells,
    timeXaddr = [multiselect[0].innerHTML, multiselect[2].innerHTML];

//=> timeXaddr now an array containing ['09:15 AM', 'Address1'];
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