How can I get the absolute URL when extracting links using Nokogiri?

问题

I'm using Nokogiri to extract links from a page but I would like to get the absolute path even though the one on the page is a relative one. How can I accomplish this?

回答1:

Nokogiri is unrelated, other than the fact that it gives you the link anchor to begin with. Use Ruby's URI library to manage paths:

absolute_uri = URI.join( page_url, href ).to_s

Seen in action:

require 'uri'

# The URL of the page with the links
page_url = 'http://foo.com/zee/zaw/zoom.html'

# A variety of links to test.
hrefs = %w[
  http://zork.com/             http://zork.com/#id
  http://zork.com/bar          http://zork.com/bar#id
  http://zork.com/bar/         http://zork.com/bar/#id
  http://zork.com/bar/jim.html http://zork.com/bar/jim.html#id
  /bar                         /bar#id
  /bar/                        /bar/#id
  /bar/jim.html                /bar/jim.html#id
  jim.html                     jim.html#id
  ../jim.html                  ../jim.html#id
  ../                          ../#id
  #id
]

hrefs.each do |href|
  root_href = URI.join(page_url,href).to_s
  puts "%-32s -> %s" % [ href, root_href ]
end
#=> http://zork.com/                 -> http://zork.com/
#=> http://zork.com/#id              -> http://zork.com/#id
#=> http://zork.com/bar              -> http://zork.com/bar
#=> http://zork.com/bar#id           -> http://zork.com/bar#id
#=> http://zork.com/bar/             -> http://zork.com/bar/
#=> http://zork.com/bar/#id          -> http://zork.com/bar/#id
#=> http://zork.com/bar/jim.html     -> http://zork.com/bar/jim.html
#=> http://zork.com/bar/jim.html#id  -> http://zork.com/bar/jim.html#id
#=> /bar                             -> http://foo.com/bar
#=> /bar#id                          -> http://foo.com/bar#id
#=> /bar/                            -> http://foo.com/bar/
#=> /bar/#id                         -> http://foo.com/bar/#id
#=> /bar/jim.html                    -> http://foo.com/bar/jim.html
#=> /bar/jim.html#id                 -> http://foo.com/bar/jim.html#id
#=> jim.html                         -> http://foo.com/zee/zaw/jim.html
#=> jim.html#id                      -> http://foo.com/zee/zaw/jim.html#id
#=> ../jim.html                      -> http://foo.com/zee/jim.html
#=> ../jim.html#id                   -> http://foo.com/zee/jim.html#id
#=> ../                              -> http://foo.com/zee/
#=> ../#id                           -> http://foo.com/zee/#id
#=> #id                              -> http://foo.com/zee/zaw/zoom.html#id

The more convoluted answer here previously used URI.parse(root).merge(URI.parse(href)).to_s.
Thanks to @pguardiario for the improvement.

回答2:

Phrogz' answer is fine but more simply:

URI.join(base, url).to_s

回答3:

You need check if the URL is absolute or relative with check if begin by http: If the URL is relative you need add the host to this URL. You can't do that by nokogiri. You need process all url inside to render like absolute.

来源：https://stackoverflow.com/questions/4861517/how-can-i-get-the-absolute-url-when-extracting-links-using-nokogiri

标签

ruby

nokogiri