Matplotlib: Repositioning a subplot in a grid of subplots

让人想犯罪 __ 提交于 2019-12-03 06:56:23

If you want to keep the for loop, you can arrange your plots with subplot2grid, which allows for a colspan parameter:

#! /usr/bin/env python
import numpy as plotting
import matplotlib
from pylab import *
x = np.random.rand(20)
y = np.random.rand(20)
fig = figure(figsize=(6.5,12))
subplots_adjust(wspace=0.2,hspace=0.2)
iplot = 420
for i in range(7):
    iplot += 1
    if i == 6:
        ax = subplot2grid((4,8), (i/2, 2), colspan=4)
    else:
        # You can be fancy and use subplot2grid for each plot, which dosen't
        # require keeping the iplot variable:
        # ax = subplot2grid((4,2), (i/2,i%2))

        # Or you can keep using add_subplot, which may be simpler:
        ax = fig.add_subplot(iplot)
    ax.plot(x,y,'ko')
    ax.set_xlabel("x")
    ax.set_ylabel("y")
savefig("subplots_example.png",bbox_inches='tight')

Use grid spec (doc) with a 4x4 grid, and have each plot span 2 columns as such:

import matplotlib.gridspec as gridspec
gs = gridspec.GridSpec(4, 4)
ax1 = plt.subplot(gs[0, 0:2])
ax2 = plt.subplot(gs[0,2:])
ax3 = plt.subplot(gs[1,0:2])
ax4 = plt.subplot(gs[1,2:])
ax5 = plt.subplot(gs[2,0:2])
ax6 = plt.subplot(gs[2,2:])
ax7 = plt.subplot(gs[3,1:3])
fig = gcf()
gs.tight_layout(fig)
ax_lst = [ax1,ax2,ax3,ax4,ax5,ax6,ax7]
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