What does an underscore concatenated to a class name mean?

自作多情 提交于 2019-12-03 05:34:11

问题


I was reading the "Dynamic, typesafe queries in JPA 2.0" article and stumbled upon this example:

EntityManager em = ...
CriteriaBuilder qb = em.getCriteriaBuilder();
CriteriaQuery<Person> c = qb.createQuery(Person.class);
Root<Person> p = c.from(Person.class);
Predicate condition = qb.gt(p.get(Person_.age), 20);
//                                     ^^ --- this one
c.where(condition);
TypedQuery<Person> q = em.createQuery(c); 
List<Person> result = q.getResultList();

I was wondering, what exactly does the underscore here mean?

Since an underscore it is a valid part of a classname I don't understand why this can be used in JPA. I checked this with an existing entity in my code and of course my class couldn't be resolved as ClassName_


回答1:


That is the metamodel for the persistance. It is how you can do type safe JPA queries in Java. It allows queries to staticly check your queries because classBar_ describes your JPA Bar. In HQL, you can easily mistype a query and not know it until it is run.

So technically, the _ does not mean anything, but it is the convention used by JPA to name a metamodel class of a JPA persistent model class. Model_ is the metamodel of Model, and it provides the names of the queryable fields and their types.




回答2:


I found this way to declare the metamodel in this article.

/**
 * A  meta model class used to create type safe queries from person
 * information.
 * @author Petri Kainulainen
 */
@StaticMetamodel(Person.class)
public class Person_ {
    public static volatile SingularAttribute<Person, String> lastName;
}


来源:https://stackoverflow.com/questions/9379536/what-does-an-underscore-concatenated-to-a-class-name-mean

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