Let user delete a selected fabric js object

Question

I have a simple fabric js based application where I will let users add shapes connect them and animate them.

Following is my JS

var canvas; 
window.newAnimation = function(){
   canvas = new fabric.Canvas('canvas');
}

window.addRect = function(){
    var rect = new fabric.Rect({
  left: 100,
  top: 100,
  fill: 'red',
  width: 20,
  height: 20,
});
    canvas.add(rect);

}

window.addCircle = function(){
    var circle = new fabric.Circle({
  radius: 20, fill: 'green', left: 100, top: 100
});
    canvas.add(circle);
}

This is my Fiddle. You can click on new animation and then add objects as of now.

I want the user to select some object and then also be able to delete it I am not sure how. I found this Delete multiple Objects at once on a fabric.js canvas in html5 But i was not able to implement it successfully. I basically want users to be able to select an object and delete it.

Answer 1

You can use the remove() method, eg.

window.deleteObject = function() {
        canvas.getActiveObject().remove();
}

jsfiddle

Answer 2

Since new version of fabric.js was released - you should use:

canvas.remove(canvas.getActiveObject());

Answer 3

Delete all selected objects:

canvas.getActiveObjects().forEach((obj) => {
  canvas.remove(obj)
});
canvas.discardActiveObject().renderAll()

Answer 4

I am using Fabric JS 2.3.6.

I wanted to allow the user to select one or more objects on the canvas and delete them by clicking the delete button.

Removed methods from old versions

The following methods are no longer available since the introduction of ActiveSelection:

setActiveGroup(group);
getActiveGroup();
deactivateAll();
discardActiveGroup();
deactivateAllWithDispatch();

Here is my code that works great for me and hopefully you as well.

$('html').keyup(function(e){
        if(e.keyCode == 46) {
            deleteSelectedObjectsFromCanvas();
        }
});    

function deleteSelectedObjectsFromCanvas(){
    var selection = canvas.getActiveObject();
    if (selection.type === 'activeSelection') {
        selection.forEachObject(function(element) {
            console.log(element);
            canvas.remove(element);
        });
    }
    else{
        canvas.remove(selection);
    }
    canvas.discardActiveObject();
    canvas.requestRenderAll();
}

Answer 5

you can delete active object by using backspace key

$(document).keydown(function(event){
    if (event.which == 8) {
        if (canvas.getActiveObject()) {
            canvas.getActiveObject().remove();
        }
    }
});