问题
When I hit the database with PagingAndSortingRepository.findAll(Pageable)
I get Page<ObjectEntity>
. However, I want to expose DTO's to the client and not entities. I can create DTO just by injecting entity into it's constructor, but how do I map the entities in Page object to DTO's? According to spring documentation, Page provides read-only operations.
Also, Page.map is not possibility, as we don't have support for java 8. How to create the new Page with mapped objects manually?
回答1:
You can still use the Page.map
without lambda expressions:
Page<ObjectEntity> entities = objectEntityRepository.findAll(pageable);
Page<ObjectDto> dtoPage = entities.map(new Converter<ObjectEntity, ObjectDto>() {
@Override
public ObjectDto convert(ObjectEntity entity) {
ObjectDto dto = new ObjectDto();
// Conversion logic
return dto;
}
});
回答2:
In Spring Data 2, the Page map method takes a Function instead of a Converter, but it still works basically the same as @Ali Dehghani described.
Using Function:
Page<ObjectEntity> entities = objectEntityRepository.findAll(pageable);
Page<ObjectDto> dtoPage = entities.map(new Function<ObjectEntity, ObjectDto>() {
@Override
public ObjectDto apply(ObjectEntity entity) {
ObjectDto dto = new ObjectDto();
// Conversion logic
return dto;
}
});
回答3:
Here is my solution, thanks to @Ali Dehghani
private Page<ObjectDTO> mapEntityPageIntoDTOPage(Page<ObjectEntity> objectEntityPage) {
return objectEntityPage.map(new Converter<ObjectEntity, ObjectDTO>() {
public ObjectDTO convert(ObjectEntity objectEntity) {
return new ObjectDTO(objectEntity, httpSession);
}
});
}
回答4:
And in java8:
Page<ObjectEntity> entities =
objectEntityRepository.findAll(pageable)
.map(ObjectDto::fromEntity);
Where fromEntity is a static method on ObjectDto that contains the conversion logic.
回答5:
You can use Page.map by simply doing this:
public Page<ObjectDto> toPageObjectDto(Page<Object> objects) {
Page<ObjectDto> dtos = objects.map(this::convertToObjectDto);
return dtos;
}
private ObjectDto convertToObjectDto(Object o) {
ObjectDto dto = new ObjectDto();
//conversion here
return dto;
}
回答6:
At the end, you will not return the Page to the users, but a list of ObjectDTO, with the Page details at the header, so this would be my solution.
ObjectService
public Page<ObjectEntity> findAll (Pageable pageable){
//logic goes here.
Page<ObjectEntity> page = objectRepository.findAll(pageable);
return page;
}
ObjectResource / rest (the exposed endpoint)
@GetMapping
public ResponseEntity<List<ObjectDTO>> findAll (Pageable pageable){
Page<ObjectEntity> page = objectServiceService.findAll(pageable);
HttpHeaders headers = PaginationUtil.generatePaginationHttpHeaders(page, "your-endpoint-here");
return new ResponseEntity<>(objectMapper.toDto(page.getContent()), headers, HttpStatus.OK);
}
The reason for using this is so that you don't need to duplicate the page details for ObjectEntity and DTO. It is key to note that a page contains the following:
- page number
- pageSize
- numberOfElements
- content
The content is the list of objects returned, and is the only thing that needs to be mapped to DTO.
来源:https://stackoverflow.com/questions/39036771/how-to-map-pageobjectentity-to-pageobjectdto-in-spring-data-rest