How to combine Futures of different types into a single Future without using zip()

问题

I want to create a Future of type Future[(Class1,Class2,Class3)] from below code. However the only way I have found to do this is by using zip(). I find the solution ugly and properly not optimal. Can anybody enlightened me.

val v = for (
    a <- {
        val f0:Future[Class1] = process1
        val f1:Future[Class2] = process2
        val f2:Future[Class3] = process3
        f0.zip(f1).zip(f2).map(x => (x._1._1,x._1._2,x._2))
    } yield a  // Future[(Class1,Class2,Class3)]

I have also tried to use Future.sequence(List(f0, f1, f2)) but this will not work as the new Future will have type of Future[List[U]] where U is the lub of Class1/2/3 whereas I want a 3-tuple preserving the original types

回答1:

val result: Future[(Class1, Class2, Class3)] = {
  val f1 = process1
  val f2 = process2
  val f3 = process3
  for { v1 <- f1; v2 <- f2; v3 <- f3 } yield (v1, v2, v3)
}

回答2:

Applicative Functors

What you are asking for is an applicative functor for a future. See scalaz Applicative Builder pattern. It should be rather trivial to roll your own on the back of zip

(f0 |@| f1 |@| f2)(g) //g is function (Class1, Class2, Class3) => Z

This is equivalent to the direct applicative:

(f0 <***> (f1, f2))(g)

Scalaz ships with a banana braces method which forms a tuple from the target and the arguments (i.e. what you asked for). So your solution will be:

f0 <|**|> (f1, f2) //that. is. all.

You get all this simply by defining a typeclass instance for the following typeclass:

trait Apply[Z[_]] {
  def apply[A, B](f: Z[A => B], a: Z[A]): Z[B]
}

So for future this looks like:

implicit val FutureApply = new Apply[Future] {
  def apply[A, B](f: Future[A => B], a: Future[A]): Future[B] = 
    (f zip a) map { case (fn, a1) => fn(a1) }
  }
}

(Actually you'd need Pure and Functor as well. Might as well implement Bind whilst you're at it - see appendix)

The great thing about this pattern is that you will start to see it everywhere (e.g. in Option, in Validation, in List etc). For example, the cartesian product of 2 streams is:

s1 <|*|> s2

Notes

All the above assuming scalaz 6, doubtless scalaz 7 for 2.10 will ship with these typeclasses by default. Pure has been renamed Pointed in scalaz7.

Appendix

Other type class instances for future:

implicit val FuturePure = new Pure[Future] {
  def pure[A](a: =>A): Future[A] = Future { a }
}
implicit val FutureBind = new Bind[Future] {
  def bind[A, B](a: Future[A], f: A => Future[B]): Future[B] = a flatMap f
}
implicit val FutureFunctor = new Functor[Future] {
  def map[A, B](a: Future[A], f: A => B): Future[B] = a map f
}

回答3:

If you are using akka look at dataflow: http://doc.akka.io/docs/akka/2.0.2/scala/dataflow.html

you need to use the Delimited Continuations plugin (but thats easy with sbt) then something like:

val f:Future[(Class1,Class2,Class3)] = flow {
  val f0 = process1
  val f1 = process2
  val f2 = process3
  (f0(), f1(), f2())
}

should compile.

in build.sbt:

autoCompilerPlugins := true

addCompilerPlugin("org.scala-lang.plugins" % "continuations" % "2.9.1")

回答4:

You could use also cats:

import cats._
import cats.instances.future._

there are few useful ways of doing this:

First more universal option:

Applicative[Future].map3(f0, f1, f2){ 
  (f0r, f1r, f2r) => //do something with results
}

and simpler :) that'll just return tuple Future[(f0.type, f1.type, f2.type)

Applicative[Future].tuple3(f0, f1, f2)

来源：https://stackoverflow.com/questions/11157552/how-to-combine-futures-of-different-types-into-a-single-future-without-using-zip

标签

scala

akka

future

applicative