One-to-one

浪子不回头ぞ 提交于 2019-11-26 17:23:02

创建模型

在本例中,Place 和 Restaurant 为一对一关系

from django.db import models

class Place(models.Model):
    name = models.CharField(max_length=50)
    address = models.CharField(max_length=80)

    def __str__(self):
        return "%s the place" % self.name

class Restaurant(models.Model):
    place = models.OneToOneField(
        Place,
        on_delete=models.CASCADE,
        primary_key=True,
    )
    serves_hot_dogs = models.BooleanField(default=False)
    serves_pizza = models.BooleanField(default=False)

    def __str__(self):
        return "%s the restaurant" % self.place.name

class Waiter(models.Model):
    restaurant = models.ForeignKey(Restaurant, on_delete=models.CASCADE)
    name = models.CharField(max_length=50)

    def __str__(self):
        return "%s the waiter at %s" % (self.name, self.restaurant)
View Code

 

数据迁移

#生成迁移文件,记录下在models.py文件中的改动
python manage.py makemigrations 

##将改动的内容作用于数据库,生成相应的数据
python manage.py migrate

 

 

表操作

 

创建数据

>>> #创建几个地点
>>> p1 = Place(name='Demon Dogs', address='944 W. Fullerton')
>>> p1.save()
>>> p2 = Place(name='Ace Hardware', address='1013 N. Ashland')
>>> p2.save()

>>> #创建一家餐厅
>>>r=Restaurant(place=p1,serves_hot_dogs=True,
serves_pizza=False)
>>> r.save()

>>>#Restaurant 可以访问 Place
>>> r.place
<Place: Demon Dogs the place>

>>>#Place 可以访问 Restaurant
>>> p1.restaurant
<Restaurant: Demon Dogs the restaurant>

>>>#P2没有关联餐厅 可以通过捕获异常,避免出错
>>> from django.core.exceptions import ObjectDoesNotExist
>>> try:
>>>     p2.restaurant
>>> except ObjectDoesNotExist:
>>>     print("There is no restaurant here.")
There is no restaurant here.

>>>#也可以通过 hasattr() 获取是否有某个属性来判断
>>> hasattr(p2, 'restaurant')
False

>>>#使用赋值符号设置place 。因为Place是restaurant的主键,所以保存将创建一个新的restaurant,将之前的restaurant
>>> r.place = p2
>>> r.save()
>>> p2.restaurant
<Restaurant: Ace Hardware the restaurant>
>>> r.place
<Place: Ace Hardware the place>

>>>#再次设置place,在反向使用赋值:
>>> p1.restaurant = r
>>> p1.restaurant
<Restaurant: Demon Dogs the restaurant>
View Code

 

查询数据

>>>#all()只返回餐馆,而不是地方。注意有两个餐馆, Ace硬件餐厅是在对r.place=p2的调用中创建的

>>> Restaurant.objects.all()
<QuerySet [<Restaurant: Demon Dogs the restaurant>, <Restaurant: Ace Hardware the restaurant>]>

>>>#all()返回所有位置,不管它们是否有餐馆
>>> Place.objects.order_by('name')
<QuerySet [<Place: Ace Hardware the place>, <Place: Demon Dogs the place>]>

>>>#可以使用跨关系查找
>>> Restaurant.objects.get(place=p1)
<Restaurant: Demon Dogs the restaurant>
>>> Restaurant.objects.get(place__pk=1)
<Restaurant: Demon Dogs the restaurant>
>>> Restaurant.objects.filter(place__name__startswith="Demon")
<QuerySet [<Restaurant: Demon Dogs the restaurant>]>
>>> Restaurant.objects.exclude(place__address__contains="Ashland")
<QuerySet [<Restaurant: Demon Dogs the restaurant>]>

>>>#反向查找也是可以的
>>> Place.objects.get(pk=1)
<Place: Demon Dogs the place>
>>> Place.objects.get(restaurant__place=p1)
<Place: Demon Dogs the place>
>>> Place.objects.get(restaurant=r)
<Place: Demon Dogs the place>
>>> Place.objects.get(restaurant__place__name__startswith="Demon")
<Place: Demon Dogs the place>

>>>#在餐厅里加一个waiter
>>> w = r.waiter_set.create(name='Joe')
>>> w
<Waiter: Joe the waiter at Demon Dogs the restaurant>

>>>#访问服务员
>>> Waiter.objects.filter(restaurant__place=p1)
<QuerySet [<Waiter: Joe the waiter at Demon Dogs the restaurant>]>
>>> Waiter.objects.filter(restaurant__place__name__startswith="Demon")
<QuerySet [<Waiter: Joe the waiter at Demon Dogs the restaurant>]>
View Code

 

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