Exception using HttpRequest.execute(): Invalid use of SingleClientConnManager: connection still allocated

风格不统一 提交于 2019-11-26 17:18:03

You need to consume the response body before you can reuse the connection for another request. You should not only read the response status, but read the response InputStream fully to the last byte whereby you just ignore the read bytes.

I was facing a similar issue when using the HttpClient with Jetty to build a test framework. I had to create multiple requests to the Servelet from my client, but It was giving the same exception when executed.

I found an alternative at http://foo.jasonhudgins.com/2010/03/http-connections-revisited.html

You can also use this following method to instantiate your client.

public static DefaultHttpClient getThreadSafeClient()  {

    DefaultHttpClient client = new DefaultHttpClient();
    ClientConnectionManager mgr = client.getConnectionManager();
    HttpParams params = client.getParams();
    client = new DefaultHttpClient(new ThreadSafeClientConnManager(params, 

            mgr.getSchemeRegistry()), params);
    return client;
}
Abdull

A similar exception message (since at least Apache Jarkata Commons HTTP Client 4.2) is:

java.lang.IllegalStateException: Invalid use of BasicClientConnManager: connection still allocated. Make sure to release the connection before allocating another one.

This exception can happen when two or more threads interact with a single org.apache.http.impl.client.DefaultHttpClient.

How can you make a 4.2 DefaultHttpClient instance threadsafe (threadsafe in the sense that two or more threads can interact with it without getting above error message)? Provide DefaultHttpClient with a connection-pooling ClientConnectionManager in the form of org.apache.http.impl.conn.PoolingClientConnectionManager!

/* using
    <dependency>
        <groupId>org.apache.httpcomponents</groupId>
        <artifactId>httpclient</artifactId>
        <version>4.2.2</version>
    </dependency>
*/

import org.apache.http.HttpResponse;
import org.apache.http.HttpStatus;
import org.apache.http.params.HttpConnectionParams;
import org.apache.http.client.HttpClient;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.impl.conn.PoolingClientConnectionManager;
import org.apache.http.impl.conn.SchemeRegistryFactory;
import org.apache.http.params.HttpParams;
import org.apache.http.client.methods.HttpGet;

public class MyComponent {

    private HttpClient client;

    {
        PoolingClientConnectionManager conMan = new PoolingClientConnectionManager( SchemeRegistryFactory.createDefault() );
        conMan.setMaxTotal(200);
        conMan.setDefaultMaxPerRoute(200);

        client = new DefaultHttpClient(conMan);

        //The following parameter configurations are not
        //neccessary for this example, but they show how
        //to further tweak the HttpClient
        HttpParams params = client.getParams();
        HttpConnectionParams.setConnectionTimeout(params, 20000);
        HttpConnectionParams.setSoTimeout(params, 15000);
    }


    //This method can be called concurrently by several threads
    private InputStream getResource(String uri) {
        try {
            HttpGet method = new HttpGet(uri);
            HttpResponse httpResponse = client.execute(method);
            int statusCode = httpResponse.getStatusLine().getStatusCode();
            InputStream is = null;
            if (HttpStatus.SC_OK == statusCode) {
                logger.debug("200 OK Amazon request");
                is = httpResponse.getEntity().getContent();
            } else {
                logger.debug("Something went wrong, statusCode is {}",
                        statusCode);
                 EntityUtils.consume(httpResponse.getEntity());
            }
            return is;
        } catch (Exception e) {
            logger.error("Something went terribly wrong", e);
            throw new RuntimeException(e);
        }
    }
}

This is an often-asked question. BalusC's response is correct. Please catch HttpReponseException, and call HttpResponseException.response.ignore(). If you need to read the error message, use response.parseAsString() if you don't know the response content type, else if you do know the content type use response.parseAs(MyType.class).

A simple code snippet from YouTubeSample.java in youtube-jsonc-sample (though usually you'll want to do something smarter in a real application):

  } catch (HttpResponseException e) {
    System.err.println(e.response.parseAsString());
  }

Full disclosure: I am an owner of the google-api-java-client project.

I had the same issue with a jax-rs (resteasy) Response object in my unit tests. I solved this with a call to response.releaseConnection(); The releaseConnection()-Method is only on the resteasy ClientResponse object, so I had to add a cast from Response to ClientResponse.

Try this

HttpResponse response = Client.execute(httpGet);
response.getEntity().consumeContent();
StatusLine statusLine = response.getStatusLine();
int statusCode = statusLine.getStatusCode();
if (statusCode == 200) {
        //task
    Log.i("Connection", "OK");
    }else{
     Log.i("Connection", "Down");
    }

Ok, i have similar problem, all those solution not work, i tested on some device, problem was date in device, it was 2011 instead 2013, check also this can help.

lucasddaniel

Read the InputStream like this:

if( response.getStatusLine().getStatusCode() == 200 ) {
    HttpEntity entity = response.getEntity();
    InputStream content = entity.getContent();
    try {
        sb = new StringBuilder();
        BufferedReader bufferedReader = new BufferedReader( new InputStreamReader( content ), 8 );
        String line;
        while( ( line = bufferedReader.readLine() ) != null ) {
            sb.append( line );
        }
        bufferedReader.close();
        content.close();
    } catch( Exception ex ) {
        Log.e( "statusCode", ex.getMessage() + "" );
    }
}

just consume the response like below, that will solve the issue

response.getEntity().consumeContent();
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