day-14元组的魔法(上)

隐身守侯 提交于 2019-12-03 00:30:07
#!/user/bin/env python# -*- coding:utf-8 -*-# 列表# listli = [11,22,33,44]# tuple# 元组元素不可被修改,不能增加或者删除# 一般写元组时最后加逗号tu = (11,"22",(),[],True,22,)print(tu)# 索引v = tu[0]print(v)# 切片v = tu[0:2]print(v)# 不可以删除或增加# tu[0]=123# for循环,可迭代对象(字符串,列表,元组,)for i in tu:    print(i)# 转换s = "asdfghjkl0"li = ["alex",123456]tu = (11,22,33,"alex")v = tuple(li)print(v)v = tuple(s)print(v)v = list(tu)print(v)v = list(s)print(v)# 字符串的拼接tu = ("asdfgh","zxcvbn")v = "_".join(tu)print(v)li = ["asdfgh","zxcvbn"]li.extend((11,22,33,))print(li)# 元组是有序的# 元组的一级元素不可修改/删除/增加tu = (11,"22",(33,43),[44,45],True,32,)v = tu[3][0]print(v)# 列表的元素可以被修改tu[3][0] = 567print(tu)# count获取指定元素在元组中出现的次数tu = (11,"22",(33,43),[44,45],True,22,)v = tu.count(22)print(v)# index获取指定元素在元组中的位置tu = (11,"22",(33,43),[44,45],True,22,)v = tu.index(22)print(v)
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