How to detect browser type and its version

Question

how can i detect browser type and its version in Rails. I want to put check on the version of specific browser and if its not required browser version than ask user to upgrade it.. i use below specified command but as its not following a standard pattern am unable to use it.

request.env['HTTP_USER_AGENT'] 

Chrome out put is below
Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US) AppleWebKit/534.16 (KHTML, like Gecko) Chrome/10.0.648.205 Safari/534.16
Safari out put is below
Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US) AppleWebKit/533.21.1 (KHTML, like Gecko) Version/5.0.5 Safari/533.21.1
FireFox out put is below
Mozilla/5.0 (Windows NT 5.1; rv:2.0) Gecko/20100101 Firefox/4.0
Opera out put is below
Opera/9.80 (Windows NT 5.1; U; en) Presto/2.8.131 Version/11.10
Internet Explorer out put is below
Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; .NET CLR 2.0.50727)

Answer 1

Try the browser gem. Very simple and can solve your purpose.

You can find the gem Here very easy to use.

Answer 2

NOTE: Be careful some search engines see this as a type of intrusion See ( Google HTTP USER AGENT )

 if request.env['HTTP_USER_AGENT'] =~ /[^\(]*[^\)]Chrome\//

or in the case of firefox

if request.env['HTTP_USER_AGENT'] =~ /[^\(]*[^\)]*[^\t]Firefox\//

and check this here you will get all you need browser Gem

browsers_detection_gem

and here is a method which can detect all browsers so chill man

def browser_detection
  result = request.env['HTTP_USER_AGENT']
  browser_compatible = ''
  if result =~ /Safari/
    unless result =~ /Chrome/
      version = result.split('Version/')[1].split(' ').first.split('.').first
      browser_compatible = 'Application is not functional for Safari version\'s '+version if version.to_i < 5
    else
      version = result.split('Chrome/')[1].split(' ').first.split('.').first
      browser_compatible = 'Application is not functional for Chrome version\'s '+version if version.to_i < 10
    end
  elsif result =~ /Firefox/
    version = result.split('Firefox/')[1].split('.').first
    browser_compatible = 'Application is not functional for Firefox version\'s '+version if version.to_i < 5
  elsif result =~ /Opera/
    version = result.split('Version/')[1].split('.').first
    browser_compatible = 'Application is not functional for Opera version\'s '+version if version.to_i < 11
  elsif result =~ /MSIE/
    version = result.split('MSIE')[1].split(' ').first
    browser_compatible = 'Application is not functional for Microsoft Internet Explorer version\'s '+version if version.to_i < 9
  end
  browser_compatible
end

Answer 3

There is also useragent gem:

<% user_agent = UserAgent.parse(request.env["HTTP_USER_AGENT"]) %>
App: <%= user_agent.application %> # Mozilla/5.0 (Macintosh; Intel Mac OS X 10.8; rv:22.0)
Browser: <%= user_agent.browser %> # Firefox
Version: <%= user_agent.version %> # 22.0
Platform: <%= user_agent.platform %> # Macintosh
Mobile: <%= user_agent.mobile? %> # False
OS: <%= user_agent.os %> # OS X 10.8

Answer 4

What you do is actually the way to do it. Now, you can process the user agent information with a regular expression, looking for matches on Firefox, Chrome or any other browser or version you like.

Answer 5

Though this is a frontend solution, I prefer to check for a specific feature that is required, such as flexbox. You can use something like Modernizr, or just a simple JavaScript check will do (https://stackoverflow.com/a/27047981/179311).

if(!("flexWrap" in document.documentElement.style)) {
    // IE 10, Chrome 20 and Firefox 27 and anything older will hit this.
    alert('your browser is out of date');
    // maybe this is preferred
    // window.location = '/browser-unsupported'
}