Find records that do not have a corresponding record in the same table

问题

I have the following table:

 ID | JobID | Data   | ResultType
---------------------------------
  1 | 12345 | XXXX   | 0
  2 | 12345 | YYYY   | 1
  3 | 23456 | AAAA   | 0
  4 | 23456 | BBBB   | 1
  5 | 34567 | FOOB   | 0
  6 | 45678 | BARB   | 0

Now I need to build a query that delivers all JobIDs where there is no entry with a ResultType = 1

EDIT1:

So at the end, I want to result that delivers only JobIDs 34567 and 45678, because there is no record with a ResultType = 1 for those JobIDs.

Can someone point me in the right direction?

回答1:

Another way (not tested):

SELECT JobId FROM Jobs GROUP BY jobId HAVING max(ResultType) = 0

回答2:

Use this query:

SELECT JobID 
From table1 a 
WHERE NOT EXISTS
 (SELECT 1 FROM table1 b WHERE b.JobID = a.JobID AND b.ResultType = 1)

回答3:

Something like

select * from jobs where jobId not in 
          (select jobId from jobs where resultType = 1)

回答4:

SELECT JobID FROM <TableName> WHERE ResultType <> 1

Is this what you want ???

来源：https://stackoverflow.com/questions/10999281/find-records-that-do-not-have-a-corresponding-record-in-the-same-table