How can I crop an image in the center? Because I know that the box is a 4-tuple defining the left, upper, right, and lower pixel coordinate but I don't know how to get these coordinates so it crops in the center.
Assuming you know the size you would like to crop to (new_width X new_height):
import Image
im = Image.open(<your image>)
width, height = im.size # Get dimensions
left = (width - new_width)/2
top = (height - new_height)/2
right = (width + new_width)/2
bottom = (height + new_height)/2
# Crop the center of the image
im = im.crop((left, top, right, bottom))
This will break if you attempt to crop a small image larger, but I'm going to assume you won't be trying that (Or that you can catch that case and not crop the image).
One potential problem with the proposed solution is in the case there is an odd difference between the desired size, and old size. You can't have a half pixel on each side. One has to choose a side to put an extra pixel on.
If there is an odd difference for the horizontal the code below will put the extra pixel to the right, and if there is and odd difference on the vertical the extra pixel goes to the bottom.
import numpy as np
def center_crop(img, new_width=None, new_height=None):
width = img.shape[1]
height = img.shape[0]
if new_width is None:
new_width = min(width, height)
if new_height is None:
new_height = min(width, height)
left = int(np.ceil((width - new_width) / 2))
right = width - int(np.floor((width - new_width) / 2))
top = int(np.ceil((height - new_height) / 2))
bottom = height - int(np.floor((height - new_height) / 2))
if len(img.shape) == 2:
center_cropped_img = img[top:bottom, left:right]
else:
center_cropped_img = img[top:bottom, left:right, ...]
return center_cropped_img
This is the function I was looking for:
from PIL import Image
im = Image.open("test.jpg")
crop_rectangle = (50, 50, 200, 200)
cropped_im = im.crop(crop_rectangle)
cropped_im.show()
Taken from another answer
来源:https://stackoverflow.com/questions/16646183/crop-an-image-in-the-centre-using-pil