Listing all resources in a namespace

Question

I would like to see all resources in a namespace.

Doing kubectl get all will, despite of the name, not list things like services and ingresses.

If I know the the type I can explicitly ask for that particular type, but it seems there is also no command for listing all possible types. (Especially kubectl get does for example not list custom types).

Any idea how to show all resources before for example deleting that namespace?

Answer 1

Based on this comment , the supported way to list all resources is to iterate through all the api versions listed by kubectl api-resources:

kubectl api-resources enumerates the resource types available in your cluster.

this means you can combine it with kubectl get to actually list every instance of every resource type in a namespace:

kubectl api-resources --verbs=list --namespaced -o name \
  | xargs -n 1 kubectl get --show-kind --ignore-not-found -l <label>=<value> -n <namespace>

Answer 2

I ended up needing this same functionality due to failed Helm deployments that left remnants in a specific namespace. Here's a function you can put in your bash profile:

function kubectlgetall {
  for i in $(kubectl api-resources --verbs=list --namespaced -o name | grep -v "events.events.k8s.io" | grep -v "events" | sort | uniq); do
    echo "Resource:" $i
    kubectl -n ${1} get --ignore-not-found ${i}
  done
}

Usage: kubectlgetall <namespace>

Example: get all resources from the kafka namespace:

kubectlgetall kafka

Answer 3

All kubernetes objects are stored in etcd.

All objects are stored in ETCD v3 the following way:

/registry/<object_type>/<namespace>/<name>

I suggest just to take the list of all resources of some namespace from etcd v3 directly:

ETCDCTL_API=3 etcdctl --endpoints=<etcd_ip>:2379 get / --prefix --keys-only | grep -E "^/\w+/\w+/<namespace>/+"

Answer 4

A Powershell implementation of rcorre's answer would look like

kubectl api-resources --verbs=list --namespaced -o name | `
%{ kubectl get $_ --show-kind --ignore-not-found -l <label>=<value> -n <namespace> }

Answer 5

Answer of rcorre is correct but for N resources it make N requests to cluster (so for a lot of resources this approach is very slow). Moreover, not found resources (that have not instances) are very slow for getting with kubectl get.

There is a better way to make a request for multiple resources:

kubectl get pods,svc,secrets

instead of

kubectl get pods
kubectl get svc
kubectl get secrets

---

So the answer is:

#!/usr/bin/env bash

# get all names and concatenate them with comma
NAMES="$(kubectl api-resources \
                 --namespaced \
                 --verbs list \
                 -o name \
           | tr '\n' ,)"

# ${NAMES:0:-1} -- because of `tr` command added trailing comma
# --show-kind is optional
kubectl get "${NAMES:0:-1}" --show-kind

or

#!/usr/bin/env bash

# get all names
NAMES=( $(kubectl api-resources \
                  --namespaced \
                  --verbs list \
                  -o name) )

# Now join names into single string delimited with comma
# Note *, not @
IFS=,
NAMES="${NAMES[*]}"
unset IFS

# --show-kind is enabled implicitly
kubectl get "$NAMES"