I have a problem with my code in the try block. To make it easy this is my code:
try:
code a
code b #if b fails, it should ignore, and go to c.
code c #if c fails, go to d
code d
except:
pass
Is something like this possible?
You'll have to make this separate try blocks:
try:
code a
except ExplicitException:
pass
try:
code b
except ExplicitException:
try:
code c
except ExplicitException:
try:
code d
except ExplicitException:
pass
This assumes you want to run code c only if code b failed.
If you need to run code c regardless, you need to put the try blocks one after the other:
try:
code a
except ExplicitException:
pass
try:
code b
except ExplicitException:
pass
try:
code c
except ExplicitException:
pass
try:
code d
except ExplicitException:
pass
I'm using except ExplicitException here because it is never a good practice to blindly ignore all exceptions. You'll be ignoring MemoryError, KeyboardInterrupt and SystemExit as well otherwise, which you normally do not want to ignore or intercept without some kind of re-raise or conscious reason for handling those.
You can use fuckit module.
Wrap your code in a function with @fuckit decorator:
@fuckit
def func():
code a
code b #if b fails, it should ignore, and go to c.
code c #if c fails, go to d
code d
Extract (refactor) your statements. And use the magic of and and or to decide when to short-circuit.
def a():
try: # a code
except: pass # or raise
else: return True
def b():
try: # b code
except: pass # or raise
else: return True
def c():
try: # c code
except: pass # or raise
else: return True
def d():
try: # d code
except: pass # or raise
else: return True
def main():
try:
a() and b() or c() or d()
except:
pass
If you don't want to chain (a huge number of) try-except clauses, you may try your codes in a loop and break upon 1st success.
Example with codes which can be put into functions:
for code in (
lambda: a / b,
lambda: a / (b + 1),
lambda: a / (b + 2),
):
try: print(code())
except Exception as ev: continue
break
else:
print("it failed: %s" % ev)
Example with arbitrary codes (statements) directly in the current scope:
for i in 2, 1, 0:
try:
if i == 2: print(a / b)
elif i == 1: print(a / (b + 1))
elif i == 0: print(a / (b + 2))
break
except Exception as ev:
if i:
continue
print("it failed: %s" % ev)
来源:https://stackoverflow.com/questions/17322208/multiple-try-codes-in-one-block