How to fetch Java version using single line command in Linux

允我心安 提交于 2019-12-02 15:46:12
Prince John Wesley
  1. Redirect stderr to stdout.
  2. Get first line
  3. Filter the version number.

    java -version 2>&1 | head -n 1 | awk -F '"' '{print $2}'
    
Beauness_Round

This is a slight variation, but PJW's solution didn't quite work for me:

java -version 2>&1 | head -n 1 | cut -d'"' -f2

just cut the string on the delimiter " (double quotes) and get the second field.

I'd suggest using grep -i version to make sure you get the right line containing the version string. If you have the environment variable JAVA_OPTIONS set, openjdk will print the java options before printing the version information. This version returns 1.6, 1.7 etc.

java -version 2>&1 | grep -i version | cut -d'"' -f2 | cut -d'.' -f1-2

Since (at least on my linux system) the version string looks like "1.8.0_45":

 #!/bin/bash
 function checkJavaVers {
    for token in $(java -version 2>&1)
    do
        if [[ $token =~ \"([[:digit:]])\.([[:digit:]])\.(.*)\" ]]
        then
            export JAVA_MAJOR=${BASH_REMATCH[1]}
            export JAVA_MINOR=${BASH_REMATCH[2]}
            export JAVA_BUILD=${BASH_REMATCH[3]}
            return 0
        fi
    done
    return 1
}

#test
checkJavaVers || { echo "check failed" ; exit; }
echo "$JAVA_MAJOR $JAVA_MINOR $JAVA_BUILD"
~

You can use --version and in that case it's not required to redirect to stdout

java --version | head -1 | cut -f2 -d' '

From java help

-version      print product version to the error stream and exit
--version     print product version to the output stream and exit

Getting only the "major" build #:

java -version 2>&1 | head -n 1 | awk -F'["_.]' '{print $3}'
Shirish Shukla

This way works for me.

# java -version 2>&1|awk '/version/ {gsub("\"","") ; print $NF}'

1.8.0_171
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