问题
I originally had an SQL statement, this:
SELECT *, COUNT(friend_one) AS pending_count , COUNT(friend_two) AS requests_sent
FROM friends
WHERE friend_one OR friend_two = ?
AND status = ?
In which I assigned my parameters like :
$pending_friend_count_stmt->execute(array($user_id, $status_one));
However, the query was not getting the results I wanted. Someone showed me a different way of doing it, but it has the variable $user_id in it multiple times, so I do not know how to adjust the code to be able to use a parameter.
You can see the new query here:
http://rextester.com/KSM73595
Am I able to just do
SELECT COUNT(CASE WHEN `friend_one` = ? THEN 1 END) as `requests_count`,
COUNT(CASE WHEN `friend_two` = ? THEN 1 END) as `pending_count`
FROM `friends`
WHERE ? IN ( `friend_one` , `friend_two` )
AND `status` = ?
$pending_friend_count_stmt->execute(array($user_id, $user_id, $user_id $status_one));
回答1:
Using PDO you have the ability to use named parameters, however in your question you want to use 1 parameters for multiple values and that means emulation has to be on:
$db->setAttribute(PDO::ATTR_EMULATE_PREPARES, true);
Now you can do the following:
$stmt = $db->prepare("SELECT * FROM table WHERE userid = :userid AND userid = :userid");
$stmt->excecute([
':userid' => 1
]);
Resulting in:
"SELECT * FROM table WHERE userid = 1 AND userid = 1"
来源:https://stackoverflow.com/questions/40681463/assigning-the-same-parameter-value-multiple-times-in-pdo-execute