问题
I have a array of bytes.
bytes[] = [43, 0, 0, -13, 114, -75, -2, 2, 20, 0, 0]
I want to convert it to unsigned bytes in Java. this is what I did: created a new array and copy the values with & 0xFF:
this.bytes = new byte[bytes.length];
for (int i=0;i<bytes.length;i++)
this.bytes[i] = (byte) (bytes[i] & 0xFF);
but the values stay negative in the new array as well. what am I doing wrong?
回答1:
bytes in Java are always signed.
If you want to obtained the unsigned value of these bytes, you can store them in an int array:
byte[] signed = {43, 0, 0, -13, 114, -75, -2, 2, 20, 0, 0};
int[] unsigned = new int[signed.length];
for (int i = 0; i < signed.length; i++) {
unsigned[i] = signed[i] & 0xFF;
}
You'll get the following values:
[43, 0, 0, 243, 114, 181, 254, 2, 20, 0, 0]
回答2:
Java has no thing called an unsigned byte. You have to use other types like short or int to be able to hold values > 127.
来源：https://stackoverflow.com/questions/46949759/converting-an-array-of-signed-bytes-to-unsigned-bytes