问题
This should be easy but for some reason I'm having trouble finding it. I have the following:
App(models.Model):
...
Release(models.Model):
date = models.DateTimeField()
App = models.ForeignKey(App)
...
How can I query for all App objects that have at least one Release?
I started typing:
App.objects.all().annotate(release_count=Count('??????')).filter(release_count__gt=0)
Which won't work because Count doesn't span relationships, at least as far as I can tell.
BONUS:
Ultimately, I'd also like to be able to sort Apps by latest release date. I'm thinking of caching the latest release date in the app to make this a little easier (and cheaper), and updating it in the Release model's save method, unless of course there is a better way.
Edit:
I'm using Django 1.1 - not averse to migrating to dev in anticipation of 1.2 if there is a compelling reason though.
回答1:
You should be able to use:
App.objects.annotate(release_count=Count('release')).filter(release_count__gt=0)\
.order_by('-release__date')
回答2:
App.objects \
.annotate(release_count=Count('release')) \
.(release_count__gt=0) \
.order_by('-release_count')
For the bonus part, denormalizing date field looks like the only solution at the moment. And it's pretty fast too.
来源:https://stackoverflow.com/questions/2471172/django-queries-count-number-of-objects-with-fk-to-model-instance