stack

I have an abstract data type that can be viewed as a list stored left to right, with the following possible operations: Push: add a new item to the left end of the list Pop: remove the item on the left end of the list Pull: remove the item on the right end of the list Implement this using three stacks and constant additional memory, so that the amortized time for any push, pop, or pull operation is constant. The stacks have basic operations, isEmpty, Push, and Pop. Amortized time means "If I spend this amount of time, I can spend another block of it and store it in a bank of time to be used

I know that on Symbian stack size is equal to 8k. What about BlackBerry? Electro Perhaps this thread on the BlackBerry Forums is helpful: I don't believe there is any way to [ increase stack size for threads ] in the BB environment. Stack Size is initialized by the JVM, and we have no access to JVM parameters in the BB OS, AFAIK. 来源： https://stackoverflow.com/questions/1267075/stack-size-on-blackberry

I'm plotting a stack barplot in ggplot2. My dataset is like, var1 var2 var3 value treatment1 group_1 C8.0 0.010056478 treatment2 group_1 C8.0 0.009382918 treatment3 group_2 C8.0 0.003014983 treatment4 group_2 C8.0 0.005349631 treatment5 group_2 C8.0 0.005349631 var1 contains 5 treatments, these five treatments belong to two groups in var2 , and each treatment has 14 measurements in var3 , their value stored in value . I want to make a plot to compare these five treatments, and their measurements. so I plot with stack bar plot like this figure: My code: library(ggplot2) colourCount = length

I am trying to implement stack with array! Every time i execute the program runs fine but i am getting warning as null character(s) ignored enabled by default What does this warning mean?.. what am i doing wrong? My code is: #include<stdio.h> #include<stdlib.h> # define MAX 10 int top=-1; int arr[MAX]; void push(int item) { if(top==MAX-1) { printf("OOps stack overflow:\n"); exit(1); } top=top+1; arr[top]=item; }//warning int popStack() { if(top==0) { printf("Stack already empty:\n"); exit(1); } int x=arr[top]; top=top-1; return x; } void display() { int i; for(i=top;i>=0;i--) { printf("%d "

So I am trying to create a maze solver program that would solve a maze of X's and O's. What I would like to do is create a class of Points, so that I can create a 2-Dimensional array of Points which would allow printing to an output page as well as implementing the stack to be relatively simple. The simplest algorithm of the general idea I'd like to implement in the actual program itself I believe should be: 1) Move forward 2) Are you at a wall? 2a) If yes, turn left 3) Are you at the finish? 3a) If no, go to 1 3b) If yes, solved But I'm having trouble coming up with a more in-depth algorithm,

Recently an interviewer asked me where the exception object in C++ is allocated, heap or stack? I'm not sure but I answered stack since I thought there is no "new" or "malloc". Is it correct? Then he kept asking me that if it's on stack, assuming class A throw a exception object, let's say "e", and class B catch "e". Since "e" is on the stack of A, then how does B can have the access to this "e"? I'm not very clear about the second question. Could anyone can give me some example code showing that "class A throw e and class B catch it"? Also, I guessed B can catch e by copying the value or

I wonder if STMDB SP!, {R0-R8} is an atomic operation in ARM(v7), because it looks quite complex to me. So is it for example possible, that the CPU is interrupted somewhere "in the middle" and has already stored R5-R8 on the stack and the SP is now SP_old - 16 and after handling the interrupt the processor continues with R0-R4? Thanks. It is atomic, as far as interrupt handling is concerned. If I remember correctly, interrupting the instruction causes it to be aborted and re-executed after interrupt processing has finished, in order to guarantee interrupt latency. To clarify upon the slightly

So I've got this example C program. int worship(long john) { return 0 * john; } int main() { return worship(666); } The assembly looks (essentially) like this: worship(long): pushq %rbp movq %rsp, %rbp movq %rdi, -8(%rbp) movl $0, %eax popq %rbp ret main: pushq %rbp movq %rsp, %rbp movl $666, %edi call worship(long) popq %rbp ret I ran into this while reading about stack smashing. In the assembly worship(long): section where it says movq %rdi, -8(%rbp) I would expect it to be using pushq based on everything I've read so far. Is this the new way that GCC is pushing arguments onto the stack and