stack

问题 This code is supposed to print the sum of numbers from 10 to 0. It should be printing 55, but is printing 10 instead. Can you help me figure out where it's going wrong? main: # initialize values to 3 registers addi $a0,$zero,10 jal sum # call method # Print out the summation upto 10 li $v0,1 # print integer add $a1,$v0,$zero # load return value into argument syscall li $v0,10 # Exit syscall sum: addi $sp,$sp,-8 # allocate space on stack sw $ra,0($sp) # store the return address sw $a0,4($sp) #

问题 This question already has answers here : Why are the terms “automatic” and “dynamic” preferred over the terms “stack” and “heap” in C++ memory management? (6 answers) Closed 3 years ago . Just what the title says, "What is the technical definition of dynamic storage in C++?" I'm curious as to how to discuss dynamic memory allocation on the heap without making any mistakes in my explanation. 回答1: From the The C++ Programming Language: Special Edition Free store , from which memory for objects

问题 This question already has answers here : Why are the terms “automatic” and “dynamic” preferred over the terms “stack” and “heap” in C++ memory management? (6 answers) Closed 3 years ago . Just what the title says, "What is the technical definition of dynamic storage in C++?" I'm curious as to how to discuss dynamic memory allocation on the heap without making any mistakes in my explanation. 回答1: From the The C++ Programming Language: Special Edition Free store , from which memory for objects

问题 This question already has answers here : Why aren't variable-length arrays part of the C++ standard? (12 answers) Closed 10 months ago . If I have the two following statements: // OK const int ARRAYSIZE = 5; int x[ARRAYSIZE]; // NOT OK int ARRAYSIZEBAD = 5; int y[ARRAYSIZEBAD]; And I don't compile with the -pedantic-errors flag... why is the second example a bad thing? In what situation would it be preferable to use dynamic allocation with the new operator? 回答1: C++ Why are non-const array

问题 I'm developing an app in JAVAFX. Mainly, the app is using a TabPane controller. In the first tab, i'm loading a controller for a StackPane . In the StackPane i'm loading as a default, one list view with custom cells. In each cell i'm having some buttons. I want to add a new pane in the stack pane and bring it to front when a button is clicked. I tried with the toFront() and toBack() but i can't get anything working. I've check, and both panes are loaded and their content is the right one. I

问题 there is stack figuration which is Parameter #N ... ... Parameter 2 Parameter 1 Return Address Old %ebp Local Variable 1 Local Variable 2 I have no idea what `"Old %ebp"` for. if %ebp is used for accessing return address and parameters, then why don't %ebp point just return address rather than "Old %ebp" ? is it for future uses? my question are Q1. what is "Old %ebp" for and what is it? Q2. why %ebp point Old %ebp not just return address? 回答1: The ebp register (base pointer) is often used in

问题 I have a code to implement a stack using array, here the complete code : here The case is why I cannot to push more than one character, but only one character? but I've been clicking some variables are initialized using a struct for her push some characters in the form of an array: struct stackMhs { char nama[10]; char npm[10]; char telp[10]; int size; }; struct stackMhs stackMhsbaru; This is the push() function with a parameter which will be the contents of data in the function main() : void

问题 I have a code to implement a stack using array, here the complete code : here The case is why I cannot to push more than one character, but only one character? but I've been clicking some variables are initialized using a struct for her push some characters in the form of an array: struct stackMhs { char nama[10]; char npm[10]; char telp[10]; int size; }; struct stackMhs stackMhsbaru; This is the push() function with a parameter which will be the contents of data in the function main() : void

问题 Anyone could explain what happens memory wise (Stack & Heap) in this example? If I understand it correctly, java stores objects on the heap, so i1 will be on the heap... same with string? But what about i2, considering it is a class field declaration. public ExampleClass { Integer i1=new Integer(1); int i2 = 2; String str = "abc"; } 回答1: Nothing happens until you have some code like new ExampleClass() . Once you do that, a new object is allocated on the heap. Included in that will be

问题 Please have a look at the following code template <typename T> class Stack { public: Stack(int number) { maxSize = number; top = -1; stackData = new T*(maxSize); } ~Stack() { delete [] stackData; } int count() { } bool isEmpty() { if(top==-1) { return true; } else { return false; } } bool isFull() { if(top== (maxSize-1)) { return true; } else { return false; } } *T pop() { if(!isEmpty()) { return stackData[top--]; // Remove Item From Stack } } *T peek(); void push(T *pushValue) { if(!isFull()