stack

问题 Given the following data set: Request starttime Duration (ms) 1 00.000 222 2 00.005 257 3 00.001 270 4 00.003 299 5 00.292 198 6 00.327 199 7 00.318 319 8 00.333 451 9 00.511 323 I need to draw an overlapping bar graph, something akin to this overlapping bar graph (from google): However, when I try to draw the bar chart in mac excel, excel overloads the y-axis with request count and start time, rather than making start time and duration as both applied to the x-axis. In short, the y-axis is

问题 This is a great answer about smart pointers, such as unique pointers: What is a smart pointer and when should I use one?. Here is an example they provide as the simplest use of a unique pointer: void f() { { std::unique_ptr<MyObject> ptr(new MyObject(my_constructor_param)); ptr->DoSomethingUseful(); } // ptr goes out of scope -- // the MyObject is automatically destroyed. // ptr->Oops(); // Compile error: "ptr" not defined // since it is no longer in scope. } However, this begs the question:

问题 I have to write a stack for class and while I understand the concept of how a stack works, I wasn't told if they are made using an array or a linked list or something else? How are most stacks created? 回答1: ArrayDeque is a solid class implementation of the stack concept. This class has implemented stack in the most efficient way. Please look at the class implementation for the details of various methods. http://www.docjar.com/html/api/java/util/ArrayDeque.java.html More specifically, look at

问题 Short question: I have a javascript that goes very deep in recursion. How can I increase the stack size so that I can execute it (something like "ulimit -s unlimited" in Unix systems)? Long story: I have to draw a graph and I use Cytoscape JS (http://js.cytoscape.org/) coupled with the Dagre layout extension (https://github.com/cytoscape/cytoscape.js-dagre). The drawing algorithm goes deep in the recursion and I end up getting "Uncaught RangeError: Maximum call stack size exceeded" in Chrome

问题 Short question: I have a javascript that goes very deep in recursion. How can I increase the stack size so that I can execute it (something like "ulimit -s unlimited" in Unix systems)? Long story: I have to draw a graph and I use Cytoscape JS (http://js.cytoscape.org/) coupled with the Dagre layout extension (https://github.com/cytoscape/cytoscape.js-dagre). The drawing algorithm goes deep in the recursion and I end up getting "Uncaught RangeError: Maximum call stack size exceeded" in Chrome

问题 As far as i know there are two kind of variables in C, stack variables and heap variables. Stack variables are fast and managed by compiler and CPU automatically. My question about stack variables are these: Are stack variables really stored in a stack FILO data structure? If so, why we can use them without poping them and losing their values? Why stack is used for storing them? What's wrong with a dequeue or list? 回答1: You, as the programmer, don't worry about pushing or popping variables on

问题 I have a simple example where the behaviour of Rust does not match my mental image, so I am wondering what am I missing: fn make_local_int_ptr() -> *const i32 { let a = 3; &a } fn main() { let my_ptr = make_local_int_ptr(); println!("{}", unsafe { *my_ptr } ); } Result: 3 This is not what I would expect. Using the notation given in The Stack and the Heap, I would expect the stack frame to look like this: Address | Name | Value ----------------------- 0 | a | 3 inside make_local_int_ptr() ,

问题 This question already has answers here : How to understand the call stack of Visual Studio? (3 answers) Closed 3 years ago . what does the hexadecimal value (with the +) behind the function name stands for ? 00 012ff668 7795aa24 ntdll_778f0000!LdrInitShimEngineDynamic+0x726 01 012ff8a0 77956e84 ntdll_778f0000!WinSqmSetDWORD64+0x14e4 02 012ff8f4 77956cd0 ntdll_778f0000!LdrInitializeThunk+0x1c4 03 012ff8fc 00000000 ntdll_778f0000!LdrInitializeThunk+0x10 回答1: These numbers indicate offset from

问题 lets say im given a txt file with lines of strings, where i have to take the first 50 lines and print them in reverse order(to clarify: the line does not change, but the order changes...50th line becomes 1st, 49th becomes 2nd, etc...) and then again for the next 50 lines until all lines are reversed. So far i have multiple for loops going through 50 lines at a time and reversing them. But is there a more efficient way to do this? i was thinking of stacks, however i dont know how to manipulate

问题 I have a queue with some numbers for example 5,6,7,8 is in queue, 5 is q->front and 8 is q->rear.. Can I reverse them in queue but without using stacks? 回答1: Of course! But it won't be as efficient. Using a stack: O(N) time. O(1) memory. Using an associative array: O(N) time. O(1) memory. Using a fixed-size array: O(N) time. O(N) memory. Using an extendable array: O(N) time. O(N) memory. Using a queue: O(N^2) time. O(1) memory. Using an associative array will use more time than using a stack,