Debounce without initial delay
问题 Is there an operator in RxJS that debounces without delaying the "first event in a burst", but delaying (and always emitting) the "last event in a burst"? Something like this: ---a----b-c-d-----e-f--- after awesome-debounce(2 dashes) becomes: ---a----b------d--e----f while a normal debounce would be: -----a---------d-------f It's kind of a mix between throttle and debounce... 回答1: Hmmm, this is the easiest solution I can think of. The interesting part for you is the awesomeDebounce() function