runtime-error

Fatal error by Java runtime environment

由 安稳与你 提交于 2019-11-26 18:15:47
问题 I am executing a junit test case I got the following error, A fatal error has been detected by the Java Runtime Environment: Internal Error (classFileParser.cpp:3174), pid=2680, tid=2688 Error: ShouldNotReachHere() JRE version: 6.0_18-b07 Java VM: Java HotSpot(TM) Client VM (16.0-b13 mixed mode windows-x86 ) Can any body please suggest the solution to resolve 回答1: I got the same problem, but with alot of googling I found the answer! See this page Quote from the link: # An unexpected error has

IOS 8 Simulator unable to boot

由 与世无争的帅哥 提交于 2019-11-26 17:33:55
问题 When I try to run my app with Xcode 6 Beta 4 on the Simulator iOS 8.0 I always get this error: Unable to boot the iOS Simulator Actually I found some similar questions on this site and I tried all the answers and I still couldn't solve it. I had the same error with the Beta 2 version of Xcode 6 so I decided to wait. But now this is not normal anymore. Did anyone find a reason why this is happening and found the solution? 回答1: I am very happy that finally my issue resolved. Thanks to apple who

Can't create handler inside thread that has not called Looper.prepare() inside AsyncTask for ProgressDialog

由 泄露秘密 提交于 2019-11-26 12:58:41
I don't understand why I'm getting this error. I'm using AsyncTask to run some processes in the background. I have: protected void onPreExecute() { connectionProgressDialog = new ProgressDialog(SetPreference.this); connectionProgressDialog.setCancelable(true); connectionProgressDialog.setProgressStyle(ProgressDialog.STYLE_SPINNER); connectionProgressDialog.setMessage("Connecting to site..."); connectionProgressDialog.show(); downloadSpinnerProgressDialog = new ProgressDialog(SetPreference.this); downloadSpinnerProgressDialog.setProgressStyle(ProgressDialog.STYLE_SPINNER);

Modifying a char *const string

由 左心房为你撑大大i 提交于 2019-11-26 12:19:59
问题 I know that const char * is a pointer to a const char, while char *const is a constant pointer to a char. I am testing this in the following code: const char *s = \"hello\"; // Not permitted to modify the string \"hello\" char *const t = \"world\"; // Not permitted to modify the pointer t s = \"hello2\"; // Valid // t = \"world2\"; // Invalid, gives compilation error // *(s + 1) = \'a\'; // Invalid, gives compilation error *(t + 1) = \'a\'; // Why does this not work? The last line does not

PHP generated XML shows invalid Char value 27 message

由 眉间皱痕 提交于 2019-11-26 12:09:01
问题 I am generating XML using PHP library as below: $dom = new DOMDocument(\"1.0\",\"utf-8\"); Doing above results in a page which shows a message on top of the output. This page contains the following errors: error on line 16 at column 274505: PCDATA invalid Char value 27 Below is a rendering of the page up to the first error. I have tried rectifying using Tidy library.. used iconv to get the chinese character in UTF-8. 回答1: A useful function to get rid of that error is suggested on this website

where to put freeze_support() in a Python script?

由 帅比萌擦擦* 提交于 2019-11-26 11:06:06
问题 I am confused about using freeze_support() for multiprocessing and I get an Runtime Error without it. I am only running a script, not defining a function or a module. Can I still use it? Or the packages I import should have been using it? Here is the documentation. Note that the specific issue is about scikit-learn calling GridSearchCV which tries to spawn processes in parallel. I am not sure if my script needs to be frozen for this, or the some code that\'s called (from the Anaconda distro).

How to properly close socket in both client and server (python)

由 ╄→尐↘猪︶ㄣ 提交于 2019-11-26 10:05:17
问题 I am writing 2 scripts in python. Client.py Server.py There is a socket between the client and server. The scenario is this: I am having one client that ask to close the program therefore it should inform the server which by then will inform the other client, therefore I need to close the socket from client (1) to the server and then close the socket from the server to other client (imagin yourself a game of 2 people that one ask to exit the game). I am doing it like that.In Client.py: # send

Should I check if malloc() was successful?

由 旧街凉风 提交于 2019-11-26 09:55:12
问题 Should one check after each malloc() if it was successful? Is it at all possible that a malloc() fails? What happens then? At school we were told that we should check, ie.: arr = (int) malloc(sizeof(int)*x*y); if(arr==NULL){ printf(\"Error. Allocation was unsuccessful. \\n\"); return 1; } What is the practice regarding this? Can I do it this way: if(!(arr = (int) malloc(sizeof(int)*x*y)) <error> 回答1: No need to cast malloc() . Yes it is required to check whether the malloc() was successful or

codeigniter CSRF error: “The action you have requested is not allowed.”

由 本秂侑毒 提交于 2019-11-26 08:29:11
问题 i enabled the csrf_protection option in the codeigniter\'s config file, and used form_open() function to creat my forms. but when i submit the form, this error occurs: The action you have requested is not allowed. i have done the answers like this topic (taht is most related to my question): question but they didn\'t work and The problem still remains. config.php <?php if ( ! defined(\'BASEPATH\')) exit(\'No direct script access allowed\'); /* |------------------------------------------------

Is it safe to `delete this`? [duplicate]

由 ∥☆過路亽．° 提交于 2019-11-26 07:36:47
问题 This question already has answers here : Is delete this allowed? (10 answers) Closed 2 years ago . In my initial basic tests it is perfectly safe to do so. However, it has struck me that attempting to manipulate this later in a function that delete s this could be a runtime error. Is this true, and is it normally safe to delete this ? or are there only certain cases wherein it is safe? 回答1: delete this is legal and does what you would expect: it calls your class's destructor and free the
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