recursion

问题 Here is an algorithm of sorting an array with two recursive calls.I have tried to calculate its time complexity roughly but not sure.I know that two for loops will take n+n times but what to do with recursive calls and how can i calculate them? Any one can help in calculating in simple mathematical way. MySort (a[1..n] , n) { If (n <= 2) { If (first element > second) && (n = 2) then do { Interchange a[1] & a[2]; } End if } Else { Assign value to min and max by very first element of array. for

问题 Edit: rewrote from scratch, the old question wasn't useful I've got an error occuring after throwing an exception inside recursion. The exception is not caught anywhere, it should just pop up and show uncaught exception error , which it doesn't. Instead, it produces time limit hit kind of error. If I put var_dumps in my code, it looks like the exception is thrown, but then it just freezes and fails after it exceeds limit. this is part of the recursive function: if($this->prvky[$iA]->ini < 1 |

问题 I am working on the Knight's Tour problem. In my program the user can select a number n equal to 3 or higher. The number will determine the table's size by n*n in a two-dimensional array. Then the knight will start it's tour based on the starting points given by the user as long as they are higher or equal to 0. My problem comes when the knight has come to a dead end (as of turn number 12 in the visualization table in the output). I want to somehow track it's movements so that I can block the

问题 I am working on the Knight's Tour problem. In my program the user can select a number n equal to 3 or higher. The number will determine the table's size by n*n in a two-dimensional array. Then the knight will start it's tour based on the starting points given by the user as long as they are higher or equal to 0. My problem comes when the knight has come to a dead end (as of turn number 12 in the visualization table in the output). I want to somehow track it's movements so that I can block the

问题 I am trying to find all possible to solutions to the coin change problem. Example: I have the coins 1 and 2 available and I want to change 6. Right Solution: [1,1,1,1,1,1], [2,1,1,1,1,0], [2,2,1,1,0,0], ... My Code: [1,1,1,1,1,1], [1,1,1,1,0,0], [1,1,0,0,0,0], ... The last line also deletes my parameter "coinsSoFar" and I don't understand why. When I debug it sets temp to [0,0,0,0,0,0] AND coinsSoFar to [0,0,0,0,0,0], which should stay at [2,0,0,0,0,0]. Would be very thankful for help.

问题 I just wanted to make sure that I was completely solid on recursion. I have used it in a bunch of applications, but realized that when someone asked me to define it (a newer programmer asked this), I was a bit shaky on the definition and had a bit of trouble explaining it. I just wanted to reach out to a large programming community to make sure I was on the right track. From what I know, recursion in computer science is when some answers to a given problem or check (i.e. an if statement)

问题 Say, I have table T where some row can contain reference to another row in the same table. Generally speaking I want to build recursive entity. What is most appropriate and efficient way to do that using SQLite? 来源： https://stackoverflow.com/questions/40299173/sqlite-and-recursive-data

问题 I'm making an RPG in JavaScript and HTML5 canvas. For the dialog, I added a "typing" effect to appear as if NPC's dialog is being typed out automatically (letter by letter). This function is fired when a user presses a button. While the function recurs through the string.length, appending each character at the given index, I don't want the user to be able to press the button again until the function stops (reaches end index of string). To do that, I've added $("#responseButton").prop(

问题 I'm hoping to improve the performance of the below as well as return the GUID of each user. I've converted and modified the code found here for searching through groups recursively to get all the members and their details and adding them to a class collection. However I also need to capture the user's managers details so I'm calling the AD twice for each user. This doesn't seem efficient as many of the users will have the same manager. It would seem logical to get the distinct manager details

问题 I'm trying to write a function repeat(s: String, n: Int) that will concatenate string s n times and return it, but for some reason I am not getting the correct results and am getting an error that it is not tail recursive, and I'm having trouble grasping logically why this wouldn't be tail recursive. Does the recursion have to process before the concatenation can be completed? How would I solve the problem? Making the recursion repeat(s+s, n-1) wouldn't work because it would recurse s too