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Random Number Generator in C [duplicate]

由 末鹿安然 提交于 2020-01-13 06:08:20
问题 This question already has answers here : Pseudo-random number generator (10 answers) Closed 6 years ago . I'm trying to generate a random number 0 - 59, and am not satisfied with the rand() function in C. Here is the code I'm playing around with: #include <stdlib.h> #include <time.h> main() { int num; srand(time(NULL)); num = rand(); num = num % 59; printf("%d\n", num); } I've repeated the run on this code and noticed that the random numbers being generated don't really seem that random. The

Random Number Generator in C [duplicate]

由 为君一笑 提交于 2020-01-13 06:05:12
问题 This question already has answers here : Pseudo-random number generator (10 answers) Closed 6 years ago . I'm trying to generate a random number 0 - 59, and am not satisfied with the rand() function in C. Here is the code I'm playing around with: #include <stdlib.h> #include <time.h> main() { int num; srand(time(NULL)); num = rand(); num = num % 59; printf("%d\n", num); } I've repeated the run on this code and noticed that the random numbers being generated don't really seem that random. The

Generate random number, between 2 numbers? [duplicate]

由 吃可爱长大的小学妹 提交于 2020-01-13 05:43:27
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: Generating random numbers in Javascript in a specific range? Say I wanted to generate a random number from 50 to 100. I know there's: Math.random() but I could only find ways to go from 1 to 'x' 回答1: From MDN on Math.random(): // Returns a random integer between min and max // Using Math.round() will give you a non-uniform distribution! function getRandomInt(min, max) { return Math.floor(Math.random() * (max -

RNGCryptoServiceProvider: generate random numbers in the range [0, randomMax)

由 冷暖自知 提交于 2020-01-13 03:11:47
问题 I wrote the following code to generate random numbers in the [0, int.MaxValue) range, but I wasn't sure how to restrict the range to [0, randomMax) while maintaining an even distribution: private static int GetNextInt32(this RNGCryptoServiceProvider random) { var buffer = new byte[sizeof(int)]; random.GetBytes(buffer); return Math.Abs(BitConverter.ToInt32(buffer, 0)); } Thanks. 回答1: Here's one way to do it: http://www.informit.com/guides/content.aspx?g=dotnet&seqNum=775. See the section

Random number with fixed length

由 倖福魔咒の 提交于 2020-01-13 02:48:07
问题 I want to generate a random integer number with 0-9 numbers and with length = 5. I try this: function genRand(min,max) { for (var i = 1; i <= 5; i++) { var range = max - min + 1; return Math.floor(Math.random()*range) + min; } } and call: genRand(0,9); But it always returns 1 number, not 5 ( Help please! 回答1: function genRand() { return Math.floor(Math.random()*89999+10000); } 回答2: return exits the function on the first loop. 回答3: The smallest 5 digit number is 10000, the largest is 99999, or

Random number with fixed length

由 拥有回忆 提交于 2020-01-13 02:48:00
问题 I want to generate a random integer number with 0-9 numbers and with length = 5. I try this: function genRand(min,max) { for (var i = 1; i <= 5; i++) { var range = max - min + 1; return Math.floor(Math.random()*range) + min; } } and call: genRand(0,9); But it always returns 1 number, not 5 ( Help please! 回答1: function genRand() { return Math.floor(Math.random()*89999+10000); } 回答2: return exits the function on the first loop. 回答3: The smallest 5 digit number is 10000, the largest is 99999, or

Java编程思想---枚举类型

由 孤街醉人 提交于 2020-01-13 00:16:28
Java编程思想—枚举类型 基本enum特性 调用enum的values()方法，可以遍历enum实例，values方法返回enum实例数组，而且该数组中的元素严格保持在enum中声明时的顺序 public enum Shrubbery { GROUND, CRAWLING, HANGING } public class EnumClass { public static void main(String[] args) { for (Shrubbery s : Shrubbery.values()) { // ordinal方法返回一个int值 这是每个enum实例在声明时的次序 从 0 开始 System.out.println(s + "orginal " + s.ordinal()); System.out.println("_________________"); // enum类实现了Comparable接口 所以具有compareTo方法 System.out.println(s.compareTo(Shrubbery.CRAWLING ) + ""); System.out.println("_________________"); // 可以用 == 来比较enum实例 编译器会自动提供equal和hashcode方法 System.out.println(s =

Day11：The time and random module

由 拥有回忆 提交于 2020-01-12 21:47:57
''' # 1::module(.py): 1;excute related files 2;quote variables # 2::package # import ... # import module1[,module2,[module3]]... # from ...import ... # from ...import * # from web.web1.web2 import cal # from web.web1.web2.cal import add # print(cal.add()) # use: if __name__ == '__mian__' to distingwish 'bin' file #*********time module:************** # 1:*********time point: import time # print(time.time()) # 1578806899.032914 (the seconds record from 1970) # 2:*********structual time: # print(time.localtime()) # the local time # print(time.gmtime(14727782898)) # can add the parameter in it #

mysql query to select one specific row and another random row

由 ℡╲_俬逩灬. 提交于 2020-01-12 19:29:21
问题 I want to display two records. For eg select * FROM users WHERE user_id = 5 . Now i want another row randomly selected from users table but with user_id != 5 Is it possible to do in a single query. I tried using union all but i dnt get two distinct rows. Thanks 回答1: This works fine for me. The first result is always the record with ID 5, the second row is a random one. Note that if no record with the ID 5 exists, both rows will be random. SELECT * FROM users ORDER BY (user_id = 5) DESC, RAND(

How can I generate a random number without use of Math.Random?

由 瘦欲@ 提交于 2020-01-12 15:37:32
问题 My project entails that I create a basic number guessing game that uses the JOptionPane and does not use Math.Random to create the random value. How would you go about doing this? I've completed everything except the random number generator. Thanks! 回答1: Here the code for a Simple random generator: public class SimpleRandom { /** * Test code */ public static void main(String[] args) { SimpleRandom rand = new SimpleRandom(10); for (int i = 0; i < 25; i++) { System.out.println(rand.nextInt());
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